问题描述
我有经过地理坐标位置的一些二进制数据流 - 经度和纬度。我需要找到它们连接codeD的方法。
I have some binary data stream which passes geo location coordinates - latitude and longitude. I need to find the method they are encoded.
4adac812 = 74°26.2851' = 74.438085
2b6059f9 = 43°0.2763' = 43.004605
4adaee12 = 74°26.3003' = 74.438338
2a3c8df9 = 42°56.3177' = 42.938628
4ae86d11 = 74°40.1463' = 74.669105
2afd0efb = 42°59.6263' = 42.993772
第一个值是十六进制值。 2楼和放大器;第三是我在（其中一个是转换使用不知道）的输出得到的值。
1st value is hex value. 2nd & 3rd are values that I get in output (not sure which one is used in conversion).
我发现，第一个字节再presents整数值（0x4a = 74）的一部分。但我无法找到部分如何小数为EN codeD。
I've found that first byte represents integer part of value (0x4a = 74). But I cannot find how decimal part is encoded.
我真的AP preciate任何帮助！
I would really appreciate any help!
感谢。
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UPD：此流来自于通过TCP协议的一些中国人的GPS服务器软件。我没有对克伦特软件源或文档。我想这是写在VC ++ 6，并使用一些标准的实现。
Upd: This stream comes from some "chinese" gps server software through tcp protocol. I have no sources or documentation for clent software. I suppose it was written in VC++6 and uses some standard implementations.
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UPD：这里是包我得到：
Upd: Here is packets I get:
Hex data:
41 00 00 00 13 bd b2 2c
4a e8 6d 11 2a 3c 8d f9
f6 0c ee 13
Log data in client soft:
[Lng] 74°40.1463', direction:1
[Lat] 42°56.3177', direction:1
[Head] direction:1006, speed:3318, AVA:1
[Time] 2011-02-25 19:52:19
Result data in client (UI):
74.669105
42.938628
Head 100 // floor(1006/10)
Speed 61.1 // floor(3318/54.3)
41 00 00 00 b1 bc b2 2c
4a da ee 12 2b 60 59 f9
00 00 bc 11
[Lng] 74°26.3003', direction:1
[Lat] 43°0.2763', direction:1
[Head] direction:444, speed:0, AVA:1
[Time] 2011-02-25 19:50:49
74.438338
43.004605
00 00 00 00 21 bd b2 2c
4a da c8 12 aa fd 0e fb
0d 0b e1 1d
[Lng] 74°26.2851', direction:1
[Lat] 42°59.6263', direction:1
[Head] direction:3553, speed:2829, AVA:1
[Time] 2011-02-25 19:52:33
74.438085
42.993772
我不知道第4个字节的意思。
I don't know what first 4 bytes mean.
我发现第5字节重新present的低7位秒的数目。 （也许5-8位的时间？）
字节9重新纬度的present整数。
I found the lower 7 bits of 5th byte represent the number of sec. (maybe 5-8 bits are time?)Byte 9 represent integer of Lat.
字节13是液化天然气的整数。
Byte 13 is integer of Lng.
颠倒（字字节）字节17-18是速度。
Bytes 17-18 reversed (word byte) is speed.
字节逆转19-20是AVA＆AMP（？）;方向（4 + 12位）。 （顺便说一句，有人知道AVA是什么？）
Bytes 19-20 reversed is ava(?) & direction (4 + 12 bits). (btw, somebody knows what ava is?)
和一个音符。在第3包13字节你可以看到只有7位用于降低。我想第1位不意味不便（我删除它在开始的时候，对不起，如果我错了）。
And one note. In 3rd packet 13th byte you can see only lower 7 bits are used. I guess 1st bit doesnt mean smth (I removed it in the beginning, sorry if I'm wrong).
推荐答案
我已经重新排列数据，以便我们首先有3个longitures然后3纬度：
I have reordered your data so that we first have 3 longitures and then 3 latitudes:
74.438085，74.438338，74.669105，43.004605，42.938628，42.993772
74.438085, 74.438338, 74.669105, 43.004605, 42.938628, 42.993772
这是十六进制的最适合我能想出是：
This is the best fit of the hexadecimals i can come up with is:
74.437368，74.439881，74.668392，42.993224，42.961388，42.982391
74.437368, 74.439881, 74.668392, 42.993224, 42.961388, 42.982391
的区别是：-0.000717，0.001543，-0.000713，-0.011381，0.022760，-0.011381
The differences are: -0.000717, 0.001543, -0.000713, -0.011381, 0.022760, -0.011381
这是从完整Hex'es（4不是3个字节）产生这些值的程序是：
The program that generates these values from the complete Hex'es (4 not 3 bytes) is:
int main(int argc, char** argv) {
int a[] = { 0x4adac812, 0x4adaee12, 0x4ae86d11, 0x2b6059f9, 0x2a3c8df9, 0x2afd0efb };
int i = 0;
while(i<3) {
double b = (double)a[i] / (2<<(3*8)) * 8.668993 -250.0197;
printf("%f\n",b);
i++;
}
while(i<6) {
double b = (double)a[i] / (2<<(3*8)) * 0.05586007 +41.78172;
printf("%f\n",b);
i++;
}
printf("press key");
getch();
}
这篇关于如何把二进制（十六进制）数据转换为纬度和经度？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！