问题描述
假设我具有以下列向量
res1 = -0.81 res2 = 0.61
0.1 -0.4
-0.91 0.62
0.2 -0.56
0.63 -0.72
,我有两个固定常数D = 0.5
.现在假设res1
的元素称为X
,而res2
的元素称为Y
.我有以下条件
and I have two fixed constant D = 0.5
. Now suppose an element of res1
is called X
and an element of res2
is called Y
. I have the following conditions
if (X > D && Y < -D)
output = 1
elseif (X < -D && Y > D)
output = -1
else
output = 0
end
我的问题是这个
是否可以将这些条件向量化"以遍历整个向量res1
和res2
,这样我的输出向量就可以给出(例如):
Is it possible to "vectorize" these conditions to iterate over the entire vectors res1
and res2
, such that my output vector would give (for example) :
output = -1
0
-1
0
1
?
我知道我可以通过循环来做到这一点,但是我宁愿避免这样做,因为这些向量实际上很大(> 10000).我曾尝试使用逻辑索引,但无济于事(除非我实施错误).
I know I can do it via a loop, but I would prefer to avoid it since these vectors are actually quite large (>10000). I have attempted to use logical indexing, but to no avail (unless I'm implementing it wrong).
任何帮助将不胜感激!
推荐答案
您可以使用 logical arrays
替换条件语句,并使用适当的比例因子对它们进行缩放以用于最终输出-
You can use logical arrays
to replace the conditional statements and scale them with appropriate scaling factors for the final output -
%// Logical arrays corresponding to the IF and ELSEIF conditional statements
case1 = res1>D & res2<-D
case2 = res1<-D & res2>D
%// Get the final output after multiplying each case with the
%// scaling factors 1 and -1 respectively.
%// The default value of `zero` for the ELSE part is automatically taken
%// care of because we are using logical array of ones and zeros anyway
output = case1 + -1*case2 %// or simply case1 - case2
样品运行-
Sample run -
>> res1
res1 =
-0.8100
0.1000
-0.9100
0.2000
0.6300
>> res2
res2 =
0.6100
-0.4000
0.6200
-0.5600
-0.7200
>> output
output =
-1
0
-1
0
1
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