问题描述
我想做这样的事情:
c:\data\> python myscript.py *.csv
并将目录中的所有.csv文件传递到我的python脚本(这样sys.argv包含["file1.csv", "file2.csv"]等)
and pass all of the .csv files in the directory to my python script (such that sys.argv contains ["file1.csv", "file2.csv"], etc.)
但是sys.argv只是收到["*.csv"]，指示通配符没有展开，因此这是行不通的.
But sys.argv just receives ["*.csv"] indicating that the wildcard was not expanded, so this doesn't work.
我觉得有一个简单的方法可以执行此操作，但是无法在Google上找到它.有什么想法吗?
I feel like there is a simple way to do this, but can't find it on Google. Any ideas?
推荐答案
您可以使用glob模块，这样，您就不必依赖特定shell的行为了(嗯，您仍然依赖于shell不会扩展参数，但至少可以通过转义通配符:-)来使这种情况在Unix中发生.
You can use the glob module, that way you won't depend on the behavior of a particular shell (well, you still depend on the shell not expanding the arguments, but at least you can get this to happen in Unix by escaping the wildcards :-) ).
from glob import glob
filelist = glob('*.csv') #You can pass the sys.argv argument
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