如果我们直接调用run方法会怎样?

问题描述

我有一个"TestRunnable"类，它通过实现Runnable覆盖了run方法.运行覆盖的运行方法，如下所示:

I have a class "TestRunnable" which overrides run method by implementing Runnable.Running overridden run method, as follow :

TestRunnable nr = new TestRunnable();
Thread t = new Thread(nr);
t.setName("Fred");
t.start();

• 如果我直接拨打t.run();
该怎么办
• 如果我们不拨打t.start();会发生什么?
• What if i directly call t.run();
• What happen if we don't call t.start(); ?

推荐答案

run方法只是另一种方法.如果直接调用它，那么它将不在另一个线程中执行，而是在当前线程中执行.

The run method is just another method. If you call it directly, then it will execute not in another thread, but in the current thread.

这是我的考试TestRunnable:

class TestRunnable implements Runnable
{
   public void run()
   {
      System.out.println("TestRunnable in " + Thread.currentThread().getName());
   }
}

仅调用start时的输出:

TestRunnable in Fred

仅调用run时的输出:

TestRunnable in main

如果未调用start，则创建的Thread将永远不会运行.主线程将完成，Thread将被垃圾回收.

If start isn't called, then the Thread created will never run. The main thread will finish and the Thread will be garbage collected.

如果两者都不被调用，则输出:(无)

Output if neither is called: (nothing)

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