问题描述
我想将一个std :: map的内容复制到另一个。可以使用 std :: copy
吗?显然,以下代码将无法正常工作:
I would like to copy the content of one std::map into another. Can I use std::copy
for that? Obviously, the following code won't work:
int main() {
typedef std::map<int,double> Map;
Map m1;
m1[3] = 0.3;
m1[5] = 0.5;
Map m2;
m2[1] = 0.1;
std::copy(m1.begin(), m1.end(), m2.begin());
return 0;
}
这不行,因为 copy
将在 m2.begin()
上调用 operator *
来取消引用它并分配一个值所有值都是类型 std :: pair< const int,double>
)。然后它将调用 operator ++
移动到 m2
中的下一个空格。由于 const int
中的 const
,这两个操作都不起作用,并且没有任何新的空格元素。
This won't work because copy
will call operator*
on m2.begin()
to "dereference" it and assign a value (all values are of type std::pair<const int, double>
). Then it will call operator++
to move to the next space in m2
. Both of these operations don't work because of the const
in const int
and there is no space reserved for any new elements.
有没有办法让它与 std :: copy
一起工作?
Is there any way to make it work with std::copy
?
谢谢!
推荐答案
您可以使用GMan的答案---但问题是,为什么您要使用 std :: copy
?您应该使用成员函数。
You can use GMan's answer --- but the question is, why do you want to use std::copy
? You should use the member function std::map<k, v>::insert
instead.
m2.insert(m1.begin(), m1.end());
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