问题描述
我想使用visual c ++以二进制模式读取整个jpg文件。代码如下:
I am trying to read an entire jpg file in binary mode using visual c++. The code is as follows:
FILE *fd = fopen("c:\\Temp\\img.jpg", "rb");
if(fd == NULL) {
cerr << "Error opening file\n";
return;
}
fseek(fd, 0, SEEK_END);
long fileSize = ftell(fd);
int *stream = (int *)malloc(fileSize);
cout << fileSize << '\n';
fseek(fd, 0, SEEK_SET);
int bytes_read = fread(stream, fileSize, 1, fd);
printf("%i\n", bytes_read);
fclose(fd);
问题是 bytes_read
1. fileSize
变量包含正确的文件大小。所以我不知道为什么 bytes_read
总是1,不等于fileSize ..
The problem is that the bytes_read
is always 1. The fileSize
variable contains the correct size of the file. So I am not sure why the bytes_read
is always 1 and not equal to fileSize..?
推荐答案
int n_read = fread(stream, fileSize, 1, fd);
返回您获得的大小fileSize的块数。在这种情况下1。
returns the number of chunks of size fileSize you got. In this case 1.
查看C标准的第7.21.8.1节:
http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1548.pdf
Look at section 7.21.8.1 of the C standard:http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1548.pdf (page 334)
因此,您需要将 n_read
乘以 fileSize
获取读取的字节数。
So you need to multiply n_read
with fileSize
to get the number of bytes read.
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