dlopen/dlsym/dlclose(dlfcn.h)导致内存泄漏

问题描述

像这样使用dlfcn系列时:

When using the dlfcn family like so:

#include <stdio.h>
#include <dlfcn.h>

typedef int(*timefunc_t)(void*);

int main()
{
    timefunc_t fun;
    void* handle;
    handle = dlopen("libc.so.6", RTLD_LAZY);
    fun = (timefunc_t)dlsym(handle, "time");
    printf("time=%d\n", fun(NULL));
    dlclose(handle);
    return 0;
}

它会导致内存泄漏:

==28803== Memcheck, a memory error detector
==28803== Copyright (C) 2002-2010, and GNU GPL'd, by Julian Seward et al.
==28803== Using Valgrind-3.6.1 and LibVEX; rerun with -h for copyright info
==28803== Command: ./dl
==28803==
time=1309249569
==28803==
==28803== HEAP SUMMARY:
==28803==     in use at exit: 20 bytes in 1 blocks
==28803==   total heap usage: 1 allocs, 0 frees, 20 bytes allocated
==28803==
==28803== LEAK SUMMARY:
==28803==    definitely lost: 0 bytes in 0 blocks
==28803==    indirectly lost: 0 bytes in 0 blocks
==28803==      possibly lost: 0 bytes in 0 blocks
==28803==    still reachable: 20 bytes in 1 blocks
==28803==         suppressed: 0 bytes in 0 blocks
==28803== Rerun with --leak-check=full to see details of leaked memory
==28803==
==28803== For counts of detected and suppressed errors, rerun with: -v
==28803== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 13 from 6)

我的问题是，这是编程错误，还是dlfcn/libdl.so中的错误?

My question is, Is this a programming error, or rather a bug in dlfcn/libdl.so?

推荐答案

类似于后者.但是，这似乎没什么大不了的，因为如果重复调用dlopen/dlsym/dlclose另一个例程，您会发现内存泄漏的大小相同，并且不会随dlopen/dlclose调用的次数而增加.

Looks like the latter. However this does not appear to be a big deal because if you repeat the dlopen/dlsym/dlclose calling another routine you'll see that the memory leak is of the same size, it does not grow with the number of dlopen/dlclose calls.

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