4和带快速路由器的套接字

4和带快速路由器的套接字

本文介绍了express.js 4和带快速路由器的套接字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用express.js 4创建一个非常简单的节点API,但是我需要一些实时事件,我添加了socket.io。我很新,所以我可能错过了一些基本的东西,但我找不到很好的文档/ tuts。



在快速应用程序快速生成器)我有一些这样的基于简单的例子和​​项目文档,我读。这可以正常工作,从客户端应用程序,我可以发送/接收套接字事件:

  c code code code code code code code code code code code $ c $ pre>  var express = require('express'); 
var router = express.Router();
var io = ???;

router.put('/ foo',function(req,res){
/ *
做更新foo资源的东西
...
* /

//现在播放更新的foo ..
io.sockets.emit('update',foo); //如何?
});

module.exports = router;


解决方案

修改你的文件一点点,你可以检查它是否有效?



您可以将您定义的io您的路线传递到下面;

  require('./ routes / api')(app,io); 

我没有测试Socket.IO部分b没有语法错误,路由也工作。



server.js文件:

  var express =表现'); 
var app = express();
var path = require('path');
var logger = require('morgan');

var io = require('socket.io')。listen(app.listen(3000));

app.use(logger('dev'));
app.use(express.static(path.join(__ dirname,'public')));

io.sockets.on('connection',function(socket){
console.log('client connect');
socket.on('echo',function (数据){
io.sockets.emit('message',data);
});
});

require('./ routes / api')(app,io);

console.log(端口3000服务器侦听);

api.js:

  module.exports = function(app,io){
app.put('/ foo',function(req,res){

/ *

做更新foo资源的东西

...

* /


//现在广播更新的foo ..

console.log(PUT OK!);

io.sockets.emit('update'); //如何?
res.json({result:通过IO发送更新});

});
}


I'm trying to create a really simple node API using express.js 4 but I need a few 'realtime' events for which I added socket.io. I'm fairly new to both so I'm likely missing something basic but I can't find good docs/tuts on this.

In the express app (created with the express generator) I have something like this based on simple examples and project docs that I read. This works OK and from client apps, I can send/receive the socket events:

var express = require('express');
var path = require('path');
var logger = require('morgan');
var api = require('./routes/api');
var app = express();
var io = require('socket.io').listen(app.listen(3000));

app.use(logger('dev'));
app.use(express.static(path.join(__dirname, 'public')));
app.use('/api', api);

io.sockets.on('connection', function (socket) {
    console.log('client connect');
    socket.on('echo', function (data) {
        io.sockets.emit('message', data);
    });
});


// error handlers omitted

module.exports = app;

but I want to use the sockets from my API routes (in the ./routes/api.js file that I 'require' above). For example, someone might use the API to PUT/POST a resource and I want that broadcast to connected socket.io clients.

I cannot see how to use the 'io' variable or organise the code currently in the io.sockets.on('connection' ... function inside express routes. Here's the ./routes/api.js file:

var express = require('express');
var router = express.Router();
var io = ???;

router.put('/foo', function(req, res) {
    /*
      do stuff to update the foo resource
      ...
     */

    // now broadcast the updated foo..
    io.sockets.emit('update', foo); // how?
});

module.exports = router;
解决方案

I've modified your files a little bit, may you check if it works?

You can pass the io you've defined to your routes like below;

require('./routes/api')(app,io);

I didn't test the Socket.IO parts but there is no syntax error and routes also working.

server.js file:

var express = require('express');
var app = express();
var path = require('path');
var logger = require('morgan');

var io = require('socket.io').listen(app.listen(3000));

app.use(logger('dev'));
app.use(express.static(path.join(__dirname, 'public')));

io.sockets.on('connection', function (socket) {
    console.log('client connect');
    socket.on('echo', function (data) {
    io.sockets.emit('message', data);
 });
});

require('./routes/api')(app,io);

console.log("Server listening at port 3000");

api.js:

module.exports = function(app,io) {
app.put('/foo', function(req, res) {

    /*

      do stuff to update the foo resource

      ...

     */


    // now broadcast the updated foo..

    console.log("PUT OK!");

    io.sockets.emit('update'); // how?
    res.json({result: "update sent over IO"});

});
}

这篇关于express.js 4和带快速路由器的套接字的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-19 20:10