将SOAP消息解组到java /或简单地解析SOAP消息？

问题描述

我面临这个问题超过一个月，所以我真的很高兴你的帮助，事实上我问的是一种可以让我解析SOAP消息（请求）的方法，可以检索所需的信息，如安全信息，如果消息正文中有任何信息和信息

I am facing this problem for over than one month , so i would be realy pleased by your help , in fact i am asking about a way that can let me parse a SOAP message (request) to can retrieve the needed information , such as the security information if there is any and informations from the body of the message

感谢您回答我，但知道我正在处理另一个问题，即WS-SecurityPolicy，我必须最终解析像这样的xml文件：
<？xml version =1.0encoding =UTF-8 ？>

Thanks for answering me , but know i am dealing with another problerm which is the WS-SecurityPolicy and i have to finaly parse an xml file like this one :<?xml version="1.0" encoding="UTF-8"?>

    <sp:TransportBinding xmlns:sp="http://schemas.xmlsoap.org/ws/2005/07/securitypolicy">
      <wsp:Policy>
        <sp:TransportToken>
          <wsp:Policy>
            <sp:HttpsToken RequireClientCertificate="false"/>
          </wsp:Policy>
        </sp:TransportToken>
        <sp:AlgorithmSuite>
          <wsp:Policy>
            <sp:Basic128/>
          </wsp:Policy>
        </sp:AlgorithmSuite>
        <sp:Layout>
          <wsp:Policy>
            <sp:Lax/>
          </wsp:Policy>
        </sp:Layout>
        <sp:IncludeTimestamp/>
      </wsp:Policy>
    </sp:TransportBinding>
    <sp:SignedSupportingTokens xmlns:sp="http://schemas.xmlsoap.org/ws/2005/07/securitypolicy">
        <wsp:Policy>
            <sp:UsernameToken sp:IncludeToken="http://schemas.xmlsoap.org/ws/2005/07/securitypolicy/IncludeToken/AlwaysToRecipient" />
      </wsp:Policy>
    </sp:SignedSupportingTokens>

'

知道这个XML文件被命名为Policy.xml并包含必须存在的WS-SecurityPolicy规则。

knowing that this XML file is named Policy.xml and contains the rules of WS-SecurityPolicy, which must be present.

推荐答案

这取决于你的内部信息。您已使用 jaxb 标记了您的问题，这使我认为您在soap消息中有xml序列化数据。如果是这种情况，您可以使用JAXB unmarshaller将消息转换为Java类的实例：

It depends on what's inside your message. You've tagged your question with jaxb which makes me think that you have xml-serialized data inside soap message. If this is the case you could use JAXB unmarshaller to convert your message to an instance of Java class:

JAXBContext jbc = JAXBContext.newInstance("com.mypackage");
Unmarshaller um = jbc.createUnmarshaller();

JAXBElement<MyClass> element = um.unmarshal(parameterNode, MyClass.class);
MyClass data = element.getValue();

这篇关于将SOAP消息解组到java /或简单地解析SOAP消息？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！