本文介绍了斯威夫特加盟阵列EXC_BAD_ACCESS的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
阵列 -join（_：）函数抛出一个EXC_BAD_ACCESS
Array –join(_:) function throws an EXC_BAD_ACCESS.
var ar1 = [1,2,3]
var ar2 = [5,6,7]
var res = ar1.join(ar2)
有没有人遇到这个问题？任何解决方案或建议？
Has anyone faced this problem? Any solution or suggestion?
推荐答案
您需要的是
var ar1 = [1,2,3]
var ar2 = [5,6,7]
var res = ar1 + ar2
您通常会通过插入另一个数组中的元素在第一级别的元素之间使用join（）方法扁平化两级数组：
You would usually use join() to flatten a two level array by inserting the elements from another array in between first level elements:
var ar1 = [1,2,3]
var ar2 = [[4,5,6],[7,8,9],[10,11,12]]
let res = ar1.join(ar2) // [4, 5, 6, 1, 2, 3, 7, 8, 9, 1, 2, 3, 10, 11, 12]
该函数以相同的方式适用于字符串也
The function works in the same fashion for strings also:
let ar1 = ["1","2","3"]
let res = ".!?".join(ar1) // "1.!?2.!?3"
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