问题描述
我正在尝试在C#.NET中编写SOAP消息(包括头文件),以使用HTTP post发送到URL。我想将其发送到的URL不是Web服务,它只接收SOAP消息以最终从中提取信息。有关如何执行此操作的任何想法?
I am trying to compose a SOAP message(including header) in C# .NET to send to a URL using HTTP post. The URL I want to send it to is not a web-service, it just receives SOAP messages to eventually extract information from it. Any ideas on how to do this?
推荐答案
首先,您需要创建有效的XML。我使用Linq to XML来实现这一点,如下所示:
First you need to create a valid XML. I use Linq to XML to achieve this, like follow:
XNamespace soapenv = "http://schemas.xmlsoap.org/soap/envelope/";
var document = new XDocument(
new XDeclaration("1.0", "utf-8", String.Empty),
new XElement(soapenv + "Envelope",
new XAttribute(XNamespace.Xmlns + "soapenv", soapenv),
new XElement(soapenv + "Header",
new XElement(soapenv + "AnyOptionalHeader",
new XAttribute("AnyOptionalAttribute", "false"),
)
),
new XElement(soapenv + "Body",
new XElement(soapenv + "MyMethodName",
new XAttribute("AnyAttributeOrElement", "Whatever")
)
)
);
然后我使用( EDIT :在此处添加 XDocument.ToString()
发送它。)
Then I send it using (EDIT: added XDocument.ToString()
down here.)
var req = WebRequest.Create(uri);
req.Timeout = 300000; //timeout
req.Method = "POST";
req.ContentType = "text/xml;charset=UTF-8";
using (var writer = new StreamWriter(req.GetRequestStream()))
{
writer.WriteLine(document.ToString());
writer.Close();
}
如果我必须阅读一些回复,我这样做(这是后续的上面的代码):
If I have to read some response, I do (this is followup of the above code):
using (var rsp = req.GetResponse())
{
req.GetRequestStream().Close();
if (rsp != null)
{
using (var answerReader =
new StreamReader(rsp.GetResponseStream()))
{
var readString = answerReader.ReadToEnd();
//do whatever you want with it
}
}
}
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