R中具有多个条件的Ifelse语句

问题描述

利用以下示例数据，我试图基于三个条件变量(Denial1，Denial2和Denial3)的值创建一个新的变量"Den"(值"0"或"1").

With the following sample data I'm trying to create a new variable "Den" (value "0" or "1") based on the values of three conditional variables (Denial1, Denial2, and Denial3).

如果三个条件变量中的任何一个都具有"0"和"1"，那么我想要一个"0"，仅当每个条件变量中具有一个值的值具有"1"(例如，不是不适用).

I want a "0" if ANY of the three conditional variables has a "0" and a "1" only if EACH conditional variable that has a value in it has a value of "1" (e.g., isn't NA).

structure(list(Denial1 = NA_real_, Denial2 = 1, Denial3 = NA_real_,
Den = NA), .Names = c("Denial1", "Denial2", "Denial3", "Den"
), row.names = 1L, class = "data.frame")

我已经尝试了以下两个命令，导致"Den"的值缺少NA:

I've tried both of the following commands that result in a missing value NA for "Den":

DF$Den<-ifelse (DF$Denial1 < 1 | DF$Denial2 < 1 | DF$Denial3 < 1, "0", "1")

DF$Den<-ifelse(DF$Denial1 < 1,"0", ifelse (DF$Denial2 < 1,"0", ifelse(DF$Denial3 < 1,"0", "1")))

有人可以演示如何做到这一点吗?

Could someone demonstrate how to do this?

推荐答案

基于@jaimedash和@Old_Mortality的建议，我找到了一个解决方案:

Based on suggestions from @jaimedash and @Old_Mortality I found a solution:

DF$Den <- ifelse(DF$Denial1 < 1 & !is.na(DF$Denial1) | DF$Denial2 < 1 &
!is.na(DF$Denial2) | DF$Denial3 < 1 & !is.na(DF$Denial3), "0", "1")

然后，如果条件变量的所有值均为NA，则确保NA的值:

Then to ensure a value of NA if all values of the conditional variables are NA:

DF$Den <- ifelse(is.na(DF$Denial1) & is.na(DF$Denial2) & is.na(DF$Denial3),
NA, DF$Den)

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