问题描述
我正在编写一个简单的程序来计算一组数字的平均值。您使用 Scanner 获取数字，因此我使用而循环使用 .hasNext（） 作为条件。然而，循环是无限的。
I am writing a simple program to calculate the average of a set of numbers. You get the numbers using Scanner, so I am using while loop with .hasNext() as a condition. However the loop is infinite.
如果没有在输入中写一些像停止这样的字，是否有可能突破它？
Is it possible to break out of it without writing some certain word like "stop" in the input?
public class main {
public static void main(String[] args){
Scanner Input = new Scanner(System.in);
int count = 0;
int temp;
int sum = 0;
while(Input.hasNextInt()){
count++;
temp = Input.nextInt();
sum += temp;
System.out.println(temp);
System.out.println(count);
} // End of while
double average = sum / count;
System.out.println("The average is: " + average);
} // End of method main
}
推荐答案
break; 语句可以起诉......嗯......突破迭代。通过迭代我的意思是你也可以从中获取，例如。
The break; statement can be sued to... well... break out of an iteration. And by iteration I mean you can get out of a for too, for example.
你必须定义WHEN你想要突破迭代，然后做这样的事情：
You have to define WHEN do you want to break out of the iteration and then do something like this:
while(Input.hasNextInt(Input)){
if(condition())
break;
count++;
temp = Input.nextInt();
sum += temp;
System.out.println(temp);
System.out.println(count);
}
否则，您可以创建一个辅助方法来定义是否迭代应继续进行，如下所示：
Otherwise, you can make an auxiliary method that defines if the iteration should keep on going, like this one:
private boolean keepIterating(Scanner in) {
boolean someOtherCondition = //define your value here that must evaluate to false
//when you want to stop looping
return Input.hasNextInt() && someOtherCondition;
}
您必须在中调用的方法：
while(keepIterating()){
count++;
temp = Input.nextInt();
sum += temp;
System.out.println(temp);
System.out.println(count);
}
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