问题描述
目前,我有这个多数民众赞成2组颜色之间的衰落:
I currently have this thats fading between 2 set colours:
for(int i=0;i<nLEDs;i++){
a = (255 / 100) * (incomingByte * sensitivity);
r = (r * 7 + a + 7) / 8;
g = (g * 7 + (255 - a) + 7) / 8;
b = 0;
FTLEDColour col = { r , g , b };
led.setLED(i, col);
}
但现在即时通讯试图让用户输入自己的颜色:
But now im trying to allow users to enter their own colours:
// > Colour fade, Start colour
int colFade1Red = 0;
int colFade1Green = 255;
int colFade1Blue = 0;
// > Colour fade, End colour
int colFade2Red = 255;
int colFade2Green = 0;
int colFade2Blue = 0;
int fadeAm = 7; // Fade speed
随衰落code:
with the fading code:
void ColourFade(){
for(int i=0;i<nLEDs;i++){
r = ctest(colFade1Red, colFade2Red, r);
g = ctest(colFade1Green, colFade2Green, g);
b = ctest(colFade1Blue, colFade2Blue, b);
FTLEDColour col = { r , g , b };
led.setLED(i, col);
}
}
int ctest(int col1, int col2, int cur){
int temp = col1 - col2;
if(temp < 0) { temp = -temp; }
int alp = (temp / 100) * (incomingByte * sensitivity);
if(col1 < col2){
return (cur * fadeAm + (col2 - alp) + fadeAm) / (fadeAm +1 );
} else {
return (cur * fadeAm + alp + fadeAm) / (fadeAm +1 );
}
}
但是,这开始于第二个用户的颜色和变淡成粉红色。我怎么会褪色的颜色是否正常?
But this starts with the Second user colour and fades into pink. How would I fade colours properly?
另外incomingByte是0和100之间的值,并且code是在一个更新循环
Also "incomingByte" is a value between 0 and 100, and the code is in a update loop.
推荐答案
这是不可能褪色到粉红色怎么一回事,因为你是从红色开始和结束绿色
It's impossible to fade to pink beacuse you are starting from red and ending with green.
要避免这种错误,我建议你写一个面向对象code。
To avoid this kind of mistake I suggest you to write an object oriented code.
如果你不想写的类来处理三维vectonr您可以使用 Arduino的补锅匠库一>
If you don't want to write the classes to handle a 3D vectonr you can use the Arduino Tinker Library
我写这个例子给你:
#include <Vect3d.h>
#include <SerialLog.h>
Tinker::Vect3d<float> red(255,0,0);
Tinker::Vect3d<float> green(0,255,0);
Tinker::SerialLog serialLog;
void setup(){
Serial.begin(9600);
serialLog.display("Fade color example");
serialLog.endline();
}
void loop(){
//fade factor computation
const uint32_t t = millis()%10000;
const float cosArg = t/10000.*3.1415*2;
const float fade = abs(cos(cosArg));
//Here's the color computation... as you can see is very easy to do!! :)
Tinker::Vect3d<uint8_t> finalColor(red*fade + green*(1-fade));
//We print the vect3d on the arduino serial port
Tinker::LOG::displayVect3d(finalColor,&serialLog);
serialLog.endline();
delay(500);
}
打印出串口以下输出
Which prints the following output on the serial port
Fade color example
V[255;0;0]
V[242;12;0]
V[206;48;0]
V[149;105;0]
V[78;176;0]
V[0;254;0]
V[79;175;0]
V[150;104;0]
V[206;48;0]
V[242;12;0]
V[254;0;0]
V[242;12;0]
V[205;49;0]
V[148;106;0]
V[77;177;0]
V[1;253;0]
V[80;174;0]
V[151;103;0]
希望这有助于:)
hope that this helps :)
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