问题描述
我已阅读以下声明.
_exit()始终成功终止进程(即 _exit() 永远不会返回).
A process is always successfully terminated by _exit() (i.e., _exit() never returns).
问题
如果_ 退出没有返回，则父进程如何获得终止状态从子进程通过 wait ?
If _exit doesn't return, how does the parent process can get the termination statusfrom the child process through the wait?
推荐答案
无论何时进程退出(无论是否通过调用_exit(int Exit_Status))，内核都会向其父级发送SIGCHLD函数.父母可以
Whenever a process exits (whether or not by calling _exit(int Exit_Status) ) the kernel sends SIGCHLD function to its parent. the parent may either
1. Ignore the incoming signal
2. Catch it by installing a signal handler
具体来说，父级可以通过调用wait()或waitpid()函数来捕获退出状态.在这种情况下，LSB可用于父级.具体地，状态可以如下获悉
Specifically the parent may catch the exit status by calling the wait()or waitpid() function. In this case the LSB is made available to the parent. Specifically the status may be learnt as follows
int status;
wpid = waitpid(child_pid, &status, WUNTRACED);
由于只有最后8位可用，因此通过按位进行255运算来掩盖高位是合乎逻辑的.系统定义的宏会为您完成
Since only the last 8 bits are available it will be logical to mask the upper bit by doing a bitwise and operation with 255. A system defined macro does this for you
WEXITSTATUS(status);
因此，为了获得子状态-您可以在waitpid语句之后使用
Thus in order to get the child status - you may use after the waitpid statement
printf("child exited, status=%d\n", WEXITSTATUS(status));
忽略SIGCHLD可能会导致创建僵尸(失效)进程.为SIGCHLD设置SA_NOCLDWAIT标志不会产生僵尸，因为内核会收获僵尸.但是，该代码不是可移植的，因此最好使用wait系统调用.
Ignoring the SIGCHLD may lead to creation of zombie (defunct) process(es). Setting SA_NOCLDWAIT flag for SIGCHLD does not produce a zombie as the kernel reaps them. However, the code is not portable and its better to use wait system call.
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