本文介绍了PHP字符串嵌套/多维数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这样的例子PHP字符串:

now $string idented just to easy view:

I want to know how can i get this string ( or other string following this style ) and transform in an array that looks like:

Array
(
    [item_1] => Array
        (
            [door] => Array
                (
                    [mozart] => Array
                        (
                            [grass] => yes
                            [green] => no
                            [human] => Array
                                (
                                    [blue] => Array
                                        (
                                            [movie] => yes
                                        )
                                )
                        )
                )
            [beat] => yes
            [music] => no
        )
)

What i tried

I tried to use and recursive function to create an nested array but i can't have access to the array pointer ( in deep levels ) in recursive functions.. don't know why.. maybe is the wrong patch to the answer.thank you,

解决方案

OK, I hope you still need this, because I wasted more time than I'd like to admin getting this right :)

Basically, my approach was to first manipulate the string into the format [set][of][keys]=value, and then loop through the string of keys and comparing them with the last set of keys to create the correct key hierarchy. I used eval because it's easier, but you can write a replacement function if you can't stomach seeing that function in your code:

//FIRST WE GET THE STRING INTO EASIER TO WORK WITH CHUNKS
$original_string = "@[item_1][door] @[mozart][grass] = yes @[mozart][green] = no @[mozart][human] @[blue][movie]=yes @[item_1][beat] = yes @[item_1][music] = no ";
$cleaned_string = str_replace('] @[','][',$original_string);
/* This results in clusters of keys that equal a value:
@[item_1][door][mozart][grass] = yes @[mozart][green] = no @[mozart][human][blue][movie]=yes @[item_1][beat] = yes @[item_1][music] = no

OR (with line breaks for clarity):

@[item_1][door][mozart][grass] = yes
@[mozart][green] = no
@[mozart][human][blue][movie]=yes
@[item_1][beat] = yes
@[item_1][music] = no */

//break it up into an array:
$elements = explode('@',$cleaned_string);

//create a variable to compare the last string to
$last_keys = "";
//and another that will serve as our final array
$array_of_arrays = array();
//now loop through each [item_1][door][mozart][grass] = yes,[mozart][green] = no, etc
foreach($elements as $element){
    if ($element==""){continue;} //skip the first empty item

    //break the string into [0] = group of keys and [1] the value that terminates the string
    //so [item_1][door][mozart][grass] = yes BECOMES [item_1][door][mozart][grass], AND yes
    $pieces = explode('=',str_replace(array('[',']'),array("['","']"),trim($element)));
    //now compare this set of keys to the last set of keys, and if they overlap merge them into a single key string
    $clean_keys = combine_key_strings($pieces[0],$last_keys);
    //set the new key string the value for the next comparison
    $last_keys = $clean_keys;
    //and (ugly, I know) we use an eval to convert "[item_1][door][mozart][grass]='yes'" into a properly keyed array
    eval("\$array_of_arrays".$clean_keys." = '".trim($pieces[1])."';");
}

//now dump the contents
print_r($array_of_arrays);


//THIS FUNCTION COMPA
function combine_key_strings($new,$old){
    //get the key that starts the newer string
    $new_keys = explode('][',$new);
    $first_key = $new_keys[0].']';

    //see if it appears in the last string
    $last_occurance = strrpos ($old,$first_key);
    //if so, merge the two strings to create the full array keystring
    if (is_int($last_occurance)){
        return substr($old,0,$last_occurance).$new;
    }
    return $new;
}

This should spit out your correctly nested array:

Array
(
    [item_1] => Array
        (
            [door] => Array
                (
                    [mozart] => Array
                        (
                            [grass] => yes
                            [green] => no
                            [human] => Array
                                (
                                    [blue] => Array
                                        (
                                            [movie] => yes
                                        )

                                )

                        )

                )

            [beat] => yes
            [music] => no
        )

)

Good night!

这篇关于PHP字符串嵌套/多维数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-19 12:58