矩阵与数组在C ++中的数组及其动态分配

问题描述

我还是不太了解矩阵和其他多维数组在C和C +中的表示方式以及如何动态分配。以下代码段：

  int main（）
 {
 int n; 
 cin>> n; 
 int a [n] [n]; 
 ... 
} 
  

如果我理解正确，乘以n的整数矩阵。
可以使用a [i] [j]访问矩阵的第（i，j）元素。编译器
自动将其转换为对实际分配的一个
维数组的第（n * i + j）个元素的访问。

假设现在我想在堆上分配n乘n矩阵a，而不是堆栈的
。我可以这样做：

  int main（）
 {
 int n; 
 cin>> n; 
 int ** a; 
 a = new int * [n]; 
 for（int i = 0; i  ... 
} 
  

现在我可以访问）元素作为a [i] [j]。然而，这不完全是
相当于上面的情况，因为我实际上必须为n * n int，
加n指针为int分配空间。此外，访问a [i] [j]现在需要两次访问内存，而
只有一次。另一方面，避免索引计算n * i + j。假设现在我对m个矩阵中的n个感兴趣，其中m很小，例如m = 2。
使用行指针数组，然后浪费33％的空间。有没有任何方式的
避免？

我当然可以分配一维数组和索引算法自己，
但这个对我来说似乎不是最好的解决方案。

任何信息将不胜感激。

解决方案

您可以创建一个为您执行索引数学的类，如果这是您不喜欢的地方。

  class Matrix 
 {
 public：
 Matrix（int iRows，int iCols）
：mRows（iRows），mCols（iCols），m * mCols]）{} 
〜Matrix（）{delete [] m; } 
 
 int& element（int iRow，int iCol）{return m [iRow * mCols + iCol]; } 
 
 int mRows，mCols，* m; 
}; 
  

There is something I still don't quite understand about the way matrices and other multidimensional arrays are represented in C and C+ and how to allocate them dynamically.

Consider the following code segment:

int main()
{
    int n;
    cin >> n;
    int a[n][n];
    ...
}

If I understand correctly, this allocates an n by n matrix of integers on the stack.The (i,j)-th element of the matrix can be accessed using a[i][j]. The compilerautomatically converts this into an access into the (n*i+j)-th element of a onedimensional array actually allocated.

Suppose now that I would like to allocate the n by n matrix a on the heap, insteadof the stack. I can then do the following:

int main()
{
    int n;
    cin >> n;
    int** a;
    a = new int*[n];
    for (int i=0;i<n;i++) a[i] = new int[n];
    ...
}

I can now access the (i,j)-th element again as a[i][j]. However, this is not exactlyequivalent to the situation above as I actually had to allocate space for n*n int's,plus n pointers to int. Also, accessing a[i][j] now entails two accesses to memory insteadof just one. On the other hand, the index computation n*i+j is avoided.

Suppose now that I am interested in n by m matrices where m is small, e.g., m=2.Using the array of row pointers then wastes 33% of the space. Is there any way ofavoiding that?

I can of course allocate a one-dimensional array and do the index arithmetic myself,but this does not seem to be the best solution to me.

Any information would be appreciated!

解决方案

You could create a class that did the index math for you, if that's where you're not liking things.

class Matrix
{
    public:
        Matrix(int iRows, int iCols)
        : mRows(iRows), mCols(iCols), m(new int[mRows*mCols]) { }
        ~Matrix() { delete [] m; }

        int &element(int iRow, int iCol) { return m[iRow * mCols + iCol]; }

        int mRows, mCols, *m;
};

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