问题描述
我在R中有一个数据框，就像所谓的 UK_profiles ：
I have a data frame in R like so called UK_profiles:
row.names id name
1 1 8131437 Profile
2 2 8131719 WolverineCompetition
3 4 8132011 www.vaseline.com
4 10 23265829 www.keepingskinamazing.co.uk
5 23 8042743 Mobile
6 24 8043312 Test
7 25 90914664 Join Our Core
8 26 45272695 UDF
9 27 50547829 apps.euro-bureau.eu/fairathon
10 28 50916438 www.benjerry.intashop.com/
11 44 83667343 All Web Site Data
12 45 84556272 UK
使用dplyr我希望过滤并使用 grepl 删除行：
Using dplyr I wish to filter and delete rows with grepl using:
require(dplyr)
UK_profiles.filtered <- filter(UK_profiles, !grepl("Rollup|Microsite|Mobile|Test|tset|Profile|Facebook|Unfiltered|returnurl", name))
但是，我收到一条错误消息：
However, I get an error saying:
对象名称。
我也得到：
对象'name'显然在数据框中。有人可以帮忙吗？
The object 'name' is clearly in the dataframe. Can someone please help?
推荐答案
似乎您正在获取 stats :: filter 函数而不是 dplyr 函数。为了确保您选择的是正确的，请使用符号 dplyr :: filter 。
It does seem like you are getting the stats::filter function and not the dplyr one. To make sure you get the right one, use the notation dplyr::filter.
d = data.frame(x=1:10,
name=c("foo","bar","baz","bar","bar","baz","fnord","qar","qux","quux"))
filter(d, !grepl("ar|ux", name))
Error in grepl("ar|ux", name) : object 'name' not found
dplyr::filter(d, !grepl("ar|ux", name))
x name
1 1 foo
2 3 baz
3 6 baz
4 7 fnord
您甚至不需要执行 library（dplyr）即可工作-您确实需要安装 dplyr
You don't even need to do library(dplyr) for this to work - you do need dplyr installed though.
此功能适用于任何软件包中的功能。
This works for functions from any package.
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