WAP打印系列的总和s = -x + x ^ 2-x ^ 3 + x ^ 4 .... N个术语

问题描述

我是这样做的...但是当我输入x = 2和n = 2时它显示3..ans应该是2 ..



我尝试了什么：

I did it in this way... but when i enter x=2 and n=2 it shows 3..ans should be 2..

What I have tried:

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int x,n,i,sum=0;
clrscr();
printf("enter the value of x and n");
scanf("%d %d",&x,&n);
for(i=1;i<=n;i++)
 {
 if(i%2==0)
    sum=sum+pow(x,i);
else
   sum=sum-pow(x,i);
}
printf("%d",sum);
getch();
}

推荐答案

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
	int x,n,i,sum=0;
	clrscr();
	printf("enter the value of x and n");
	scanf("%d %d",&x,&n);
	for(i=1;i<=n;i++)
	{
		if(i%2==0)
			sum=sum+pow(x,i);
		else
			sum=sum-pow(x,i);
	}
	printf("%d",sum);
	getch();
}

第二：避免使用单字母变量：一个聪明的名字可以让你更轻松地理解你的代码。

---- -

当你不明白你的代码在做什么或为什么它做它的作用时，答案是调试器。

使用调试器，看看你的代码在做什么。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量，这是一个令人难以置信的学习工具。



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调试器在这里显示你的代码正在做什么，你的任务是与它应该做什么进行比较。

调试器中没有魔法，它没有发现错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。

Second: avoid single letter variables: a clever name can ease the understanding of your code.
-----
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool.

Debugger - Wikipedia, the free encyclopedia[^]
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]

The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

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