如何使用天花板，地板数学函数| VB.NET

问题描述

再次问好，我需要在我的问题中使用这些数学函数。



首先，我有一个值列表，首先我使用abs和log10数学函数。

现在，我需要在该数组中使用这2个方程。



1. x = ceil（30 * log10 （arrData））+ 1

2. y = floor（30 * log10（arrData））



然后，我需要制作这个计算：newsetdata = y-x + 1



我创建了2个列表，第一个是使用了天花板的arrData，而arrData2是底层。 br />


现在我想创建一个新列表，我可以使用这个等式 - > arrData2-arrData + 1我无法做到这一点...一些帮助？



我尝试了什么：

Hello again, I need to use these math functions in my problem.

First of all, I have an list of values which first I use the abs and log10 math functions.
Now, I need to use these 2 equations in that array.

1. x=ceil(30*log10(arrData))+1
2. y=floor(30*log10(arrData))

And then, I need to make this calculation : newsetdata=y-x+1

I create 2 lists, the 1st is the arrData which I used the ceiling , and the arrData2 is the floor.

now I want to create a new list that I can use this equation -> arrData2-arrData+1 and I can't do this...some help?

What I have tried:

Dim strFileName = IO.File.ReadAllLines("C:\Users\x-ios\Desktop\1234.txt")
Dim cu As Globalization.CultureInfo = Globalization.CultureInfo.CreateSpecificCulture("en-US")
Dim style As Globalization.NumberStyles = Globalization.NumberStyles.Number Or Globalization.NumberStyles.AllowCurrencySymbol

Dim arrData = strFileName _
.Select(Function(x) New With _
{
.FirstCol = Math.Ceiling(Math.log10(Math.Abs(Double.Parse(x.Split(New String(){Microsoft.VisualBasic.vbTab}, StringSplitOptions.RemoveEmptyEntries)(0), style, cu))), _
.SecondCol = Math.Ceiling(Math.log10(Math.Abs(Double.Parse(x.Split(New String(){Microsoft.VisualBasic.vbTab}, StringSplitOptions.RemoveEmptyEntries)(1), style, cu)))) _
}) _
.ToList()


Dim arrData2 = strFileName _
.Select(Function(x) New With _
{
.FirstCol = Math.Floor(Math.log10(Math.Abs(Double.Parse(x.Split(New String(){Microsoft.VisualBasic.vbTab}, StringSplitOptions.RemoveEmptyEntries)(0), style, cu)))), _
.SecondCol = Math.Floor(Math.log10(Math.Abs(Double.Parse(x.Split(New String(){Microsoft.VisualBasic.vbTab}, StringSplitOptions.RemoveEmptyEntries)(1), style, cu)))) _
}) _
.ToList()

推荐答案

Quote：

是的，我提到x = ceil（30 * log10（arrData））+ 1，y = floor（30 * log10（arrData） ）），我完成了它们（arrData是x，y是arrData2）。现在我需要：newdataset = y-x + 1

（我更新问题，因为我忘了提到它，错误）

Yes, I mentioned that x=ceil(30*log10(arrData))+1 , y=floor(30*log10(arrData)), and I accomplished them (arrData is the x ,and y is the arrData2) . And now I need : newdataset=y-x+1
(I update the question, because I forgot to mentioned it, by mistake)

计算结果所需的全部是：

All you need to calculate result is:

Dim arrData = strFileName _
	.Select(Function(x) New With _
		{
			.a = Double.Parse(x.Split(New String(){Microsoft.VisualBasic.vbTab}, StringSplitOptions.RemoveEmptyEntries)(0), style, cu), _
			.b = Double.Parse(x.Split(New String(){Microsoft.VisualBasic.vbTab}, StringSplitOptions.RemoveEmptyEntries)(1), style, cu) _
		}) _
	.ToList()

	For Each d In arrData
		Dim x = Math.Ceiling(30*Math.Log10(d.a))+1
		Dim y = Math.Floor(30*Math.Log10(d.b))
		Console.WriteLine("{0}-{1}+1={2}", y, x, y-x+1)
	Next

Reult：

Reult:

-11--38+1=28
-8--35+1=28
-5--33+1=29
-3--31+1=29
-1--30+1=30
0--29+1=30
...

如果我误解了您，请根据需要更改代码。

Change the code to your needs, if i misunderstood you.

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