如何C ++隐式转换c样式字符串为字符串对象？

问题描述

  string s =abc; 
  

上述语句将首先调用 string（const char * s） code>构造函数，然后根据。

有几种情况是合法的初始化。在所有情况下，RHS必须可转换为 string 才能正常工作。

一个字符串文字可以转换为 string 是通过 string 的构造函数获取 char const * 。这称为。

string s = "abc";

The above statement will first invoke string ( const char * s ) constructor, then invoke copy constructor according to What are the differences in string initialization in C++? .Here is the question: how C++ know it should invoke string ( const char * s ) to convert literal string "abc" to a temporary string object?

Note:copy constructor won't be invoked in copy initialization.

解决方案

Initializing an object by using the syntax

string s = "abc";

is called copy initialization.

There are several scenarios where that is legal initialization. In all cases the RHS must be convertible to a string for it to work.

One way a string literal can be converted to a string is through the constructor of string that takes a char const*. That is called a user defined conversion.

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