jQuery/以编程方式在“选择"框中选择一个选项

问题描述

我目前正在使用jQuery返回一些JSON结果.返回这些结果后，我将使用它们来预填充表单中的字段.

I'm currently using jQuery to return some JSON results. Once these results are returned, I'm using them to pre-populate fields in my form.

但是，在下拉框中预选项目时，我需要一些帮助.例如，我有一个选择框(缩短了):

However, I need some help in pre-selecting items in a drop down box. For example, I have a select box (this is shortened):

<select id="startTime">
<option value="14:00:00">2:00 pm</option>
<option value="15:00:00">3:00 pm</option>
<option value="16:00:00">4:00 pm</option>
<option value="17:00:00">5:00 pm</option>
<option value="18:00:00">6:00 pm</option>
</select>

如果我的JSON值为:

And if my JSON value is:

 var start_time = data[0].start  // Let's say this is '17:00:00'

我如何使用jQuery将选项设置为'17:00:00'?

How can I, using jQuery, make the option with value '17:00:00' selected?

 <option value="17:00:00" selected="selected">5:00 pm</option>

推荐答案

更新:

从jQuery 1.9开始，jQuery已更新，更改了此功能.选项的选择"状态实际上是一个属性，因此jQuery将其更改为使用.prop()方法.语法非常相似且易于切换:

As of jQuery 1.9, jQuery has updated changed this functionality. The "selected" state of an option is actually a property, therefore jQuery has changed this to use the .prop() method. Syntax is very similar and easy to switch:

$('#startTime option[value=17:00:00]').prop('selected', true);

请参见 http://api.jquery.com/prop/#entry-longdesc为什么需要通过true.

See http://api.jquery.com/prop/#entry-longdesc for why it needs to pass true.

旧版jQuery

$('#startTime option[value=17:00:00]').attr('selected', 'selected');

或

$('#startTime option[value='+ data[0].start +']').attr('selected', 'selected');

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