本文介绍了mysql_real_escape_string()的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我创建了一个评论表单,它会将评论插入数据库

并立即显示。我想确保用户将不需要的数据插入数据库或执行查询是安全的。


这是我的PHP代码,这是做对了吗?还有什么我应该为了让它更安全吗?


$ handle = mysql_connect($ host,$ user,$ password)或die( 对不起,看起来好像

就像发生错误一样。');


$ sql =" INSERT INTO评论(id,comment,name,quotekey) )VALUES(NULL,

''$ comment'',''name'',''$ key'')" ;;


mysql_real_escape_string ($ sql);

mysql_select_db($ database);

mysql_query($ sql);


mysql_close ($ handle);


谢谢,

Zach Wingo

I created a comment form which will inserts the comments into a database
and displays them immediately. I want to make sure that its safe from
users inserting unwanted data into the database or executing queries.

Here''s my php code, is this done right? Is there anything else I should
to to make it more secure?

$handle = mysql_connect($host,$user,$password) or die (''Sorry, looks
like an error occurred.'');

$sql = "INSERT INTO comments (id, comment, name, quotekey) VALUES (NULL,
''$comment'', ''$name'', ''$key'')";

mysql_real_escape_string($sql);
mysql_select_db($database);

mysql_query($sql);

mysql_close($handle);

Thanks,
Zach Wingo

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08-19 08:52