本文介绍了使用MongoDB C ++驱动程序在BSON文档中查找的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的MongoDB测试数据库中有以下文档:
I have the following document in my MongoDB test database:
db.a.find()
{[ {
"_id" : ObjectId("5113d680732fb764c44qweq"),
"Builds" : [
{
"level" : 1,
"rank" : 2
},
{
"level" : 3,
"rank" : 4
}
],
"abs" : [
{
"level" : 3,
"status" : 5
},
{
"level" : 3,
"status" : 4
}
]
}, {
"_id" : ObjectId("5113d680732fb764c4464fdf"),
"Builds" : [
{
"level" : 3,
"rank" : 5
},
{
"level" : 3,
"rank" : 4
}
],
"abs" : [
{
"level" : 3,
"status" : 5
},
{
"level" : 3,
"status" : 4
}
]
}
]}
我需要找到构建级别> = 2和< = 5且绝对状态> = 5就像if(builds.leve> = 2&&builds.level< = 5&& abs.status> = 5&&abs.level> = 2)多种条件并且需要取值的大小你能帮我吗?
I need find Builds level >=2 and <= 5 and abs status >=5it like if(builds.leve >=2 && builds.level <= 5 && abs.status >=5 && abs.level>=2)multiple conditionsand need take a size of valuesMay you help me?
推荐答案
以下是适合您的示例.我对mongo cxx的了解不多,所以我不确定语法.
Here is an sample for you. I am not much into mongo cxx so i am not sure about the syntax.
bsoncxx::builder::stream::document filter_builder;
filter_builder << "$or" << "Builds.level"
<< open_document << "$gte" << 1 << "$lte" << 5 << close_document
<< open_document << "abs.status" << "$gte" << 2 << "$lte" << 5
<< close_document << close_array;
auto cursor = db["your collection name"].find(filter_builder.view());
for (auto&& doc : cursor) {
std::cout << bsoncxx::to_json(doc) << std::endl;
}
这篇关于使用MongoDB C ++驱动程序在BSON文档中查找的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!