Laravel 4控制器模板/刀片-正确的方法?

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问题描述

我一直在阅读Laravel 4文档，并正在开发一个演示应用程序来帮助学习.

I've been reading through the Laravel 4 documentation and have been making a demo application to help with learning.

我找不到有关刀片和控制器视图模板的大量文档.哪种方法正确，还是取决于个人喜好?

I couldn't find much documentation on the templating of views with blade and controllers.Which is the correct method or does it come down to personal preference?

例如1

Controllers/HomeController.php

protected $layout = 'layouts.main';

public function showWelcome()
{
    $this->layout->title = "Page Title";
    $this->layout->content = View::make('welcome');
}

视图/布局/main.blade.php

<html>
<head>
    <title>{{ $title }}</title>
</head>
<body>
    {{ $content }}
</body>
</html>

视图/welcome.blade.php

<p>Welcome.</p>

例如2

Controllers/HomeController.php

protected $layout = 'layouts.main';

public function showWelcome()
{
    $this->layout->content = View::make('welcome');
}

视图/布局/main.blade.php

<html>
<head>
    <title>@yield('title')</title>
</head>
<body>
    @yield('content')
</body>
</html>

视图/welcome.blade.php

@section('title', 'Welcome')
@section('content')
// content
@stop

以上内容的最佳约定和/或优势是什么?

What is the best convention and/or advantages of the the above?

推荐答案

我没有在控制器中存储任何布局信息，而是通过

I don't store any layout information in the controller, I store it in the view via

@extends('layouts.master')

当我需要在控制器中返回视图时，使用:

When I need to return a view in the controller I use:

return \View::make('examples.foo')->with('foo', $bar);

我更喜欢这种方法，因为视图确定要使用的布局，而不是要确定重构的控制器.

I prefer this approach as the view determines what layout to use and not the controller - which is subject to re-factoring.

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