问题描述
我是新的C＃。我有一个控制台应用程序一个菜单。现在，当我已经完成了挑选一个项目出菜单的，做什么菜单项要求我要循环，并再次显示菜单，以便用户可以选择一个diffenrent菜单项。我有菜单上的退出，我只是想用它来退出。我已经尝试了while循环但这并不工作。它关闭应用程序的菜单项已被选中，被选中的项目的代码运行之后。我在做什么错
I am new to C#. I have a "menu" in a console app. Now when I have finished picking an item out of the menu and doing what that menu item require I want to loop and show the menu again so that the user can choose a diffenrent menu item. I have an exit on the menu and I only want to use that to exit. I have tried a while loop but this doesnt work. It closes the app after a menu item has been chosen and the chosen items code has run. What am I doing wrong?
static void Main()
{
int input = 0;
while (true)
{
Console.WriteLine("MENU");
Console.WriteLine("Please enter the number that you want to do:");
Console.WriteLine("1. Do thing A");
Console.WriteLine("2. Do thing B");
Console.WriteLine("3. Do thing C");
Console.WriteLine("4. Do thing D");
Console.WriteLine("5. Do thing E");
Console.WriteLine("6. Do thing F");
Console.WriteLine("7. Exit");
int menuchoice = int.Parse(Console.ReadLine());
switch (menuchoice)
{
case 1:
Console.WriteLine("Thing A has been done");
break;
case 2:
Console.WriteLine("Thing B has been done");
break;
case 3:
Console.WriteLine("Thing C has been done");
break;
case 4:
Console.WriteLine("Thing D has been done");
break;
case 5:
Console.WriteLine("Thing E has been done");
break;
case 6:
Console.WriteLine("Thing F has been done");
break;
case 7:
Environment.Exit; //edit
break;
default:
Console.WriteLine("Sorry, invalid selection");
break;
}
input++;
if (input < 30)
continue;
else
break;
}
}
任何人都可以请帮助？在此先感谢
Can anyone please help? Thanks in advance!
编辑：！我知道了Console.Exit是行不通的。我也只是把它像那样illastrate，控制台必须退出那里。我的问题是我需要循环整个菜单每次选项被选中，被选中的选项代码运行之后。我只想使用exit退出。但在这一点上，菜单不循环，经过短短1选项被选中，并且选择代码运行控制台关闭
I am aware that that "Console.Exit" would not work. I did just put it like that to illastrate that the console must exit there. My problem is that I need to loop the whole menu every time after a option have been chosen and the chosen option code has run. I only want to use the exit to exit. But at this point the menu does not loop, the console closes after just 1 option have been chosen and that options code has run.
编辑：会发生什么事，当您启动程序，并按下1后的回报？这是真正的问题，菜单似乎不进行循环。我开始我的程序后，按1依次是返回的情况下，代码1运行完美，但随后控制台只是关闭。如果我再并按启动控制台2这段时间的情况下，2的代码也运行完美，但随后控制台再次关闭。我测试了我所有的情况下，像这样和他们都运行完美。
What happens when you start your program and you press 1 followed by Return? This is the real problem, the menu doesnt seem to be looping. After I start my program and press 1 followed by return the code in case 1 runs perfectly but then the console just closes. If I start the console again and press 2 this time the code in case 2 also runs perfectly but then the console closes again. I have tested all my cases like this and all of them runs perfectly.
推荐答案
请简单：直到按下7循环停留在循环
Keep it simple: the loop stays in the loop until 7 is pressed
int menuchoice = 0;
while (menuchoice != 7)
{
Console.WriteLine("MENU");
Console.WriteLine("Please enter the number that you want to do:");
Console.WriteLine("1. Do thing A");
Console.WriteLine("2. Do thing B");
Console.WriteLine("3. Do thing C");
Console.WriteLine("4. Do thing D");
Console.WriteLine("5. Do thing E");
Console.WriteLine("6. Do thing F");
Console.WriteLine("7. Exit");
menuchoice = int.Parse(Console.ReadLine());
switch (menuchoice)
{
case 1:
Console.WriteLine("Thing A has been done");
break;
case 2:
Console.WriteLine("Thing B has been done");
break;
case 3:
Console.WriteLine("Thing C has been done");
break;
case 4:
Console.WriteLine("Thing D has been done");
break;
case 5:
Console.WriteLine("Thing E has been done");
break;
case 6:
Console.WriteLine("Thing F has been done");
break;
case 7:
break; //edit
default:
Console.WriteLine("Sorry, invalid selection");
break;
}
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