问题描述
我需要在 C# 中比较 2 个字符串,并将重音字母与非重音字母一样对待.例如:
I need to compare 2 strings in C# and treat accented letters the same as non-accented letters. For example:
string s1 = "hello";
string s2 = "héllo";
s1.Equals(s2, StringComparison.InvariantCultureIgnoreCase);
s1.Equals(s2, StringComparison.OrdinalIgnoreCase);
这两个字符串必须相同(就我的应用程序而言),但是这两个语句的计算结果都为 false.C# 中有没有办法做到这一点?
These 2 strings need to be the same (as far as my application is concerned), but both of these statements evaluate to false. Is there a way in C# to do this?
推荐答案
EDIT 2012-01-20:哦,天哪!解决方案要简单得多,并且几乎永远存在于框架中.正如 Knightpfhor 所指出的:
EDIT 2012-01-20: Oh boy! The solution was so much simpler and has been in the framework nearly forever. As pointed out by knightpfhor :
string.Compare(s1, s2, CultureInfo.CurrentCulture, CompareOptions.IgnoreNonSpace);
这是一个从字符串中去除变音符号的函数:
Here's a function that strips diacritics from a string:
static string RemoveDiacritics(string text)
{
string formD = text.Normalize(NormalizationForm.FormD);
StringBuilder sb = new StringBuilder();
foreach (char ch in formD)
{
UnicodeCategory uc = CharUnicodeInfo.GetUnicodeCategory(ch);
if (uc != UnicodeCategory.NonSpacingMark)
{
sb.Append(ch);
}
}
return sb.ToString().Normalize(NormalizationForm.FormC);
}
更多详情MichKap 的博客(RIP...).
原理是将 'é' 变成 2 个连续的字符 'e',锐角.然后它遍历字符并跳过变音符号.
The principle is that is it turns 'é' into 2 successive chars 'e', acute.It then iterates through the chars and skips the diacritics.
héllo"变成hello",然后变成hello".
"héllo" becomes "he<acute>llo", which in turn becomes "hello".
Debug.Assert("hello"==RemoveDiacritics("héllo"));
注意:这是相同功能的更紧凑的 .NET4+ 友好版本:
Note: Here's a more compact .NET4+ friendly version of the same function:
static string RemoveDiacritics(string text)
{
return string.Concat(
text.Normalize(NormalizationForm.FormD)
.Where(ch => CharUnicodeInfo.GetUnicodeCategory(ch)!=
UnicodeCategory.NonSpacingMark)
).Normalize(NormalizationForm.FormC);
}
这篇关于在字符串比较中忽略重音字母的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!