问题描述
我是PHP新手.
当某人上传的文件太大时,我想向他们显示一个警告弹出窗口,并将其重定向到上一页(反之亦然).
When someone uploads a file size too big, I want to show them a warning popup and redirect them to a previous page (or vice versa).
if(file size is too big){
ob_start();
header("location:index.php");
echo "<script type='text/javascript'>alert('Your File Size is too big!');</script>";
ob_end_flush();
exit;
}
上面的代码只会将我重定向到index.php,并且不会显示任何警告弹出窗口.
This code above will just redirect me to index.php and doesn't show any warning popup.
推荐答案
执行类似操作
header("Location: index.php?Message=" . urlencode($Message));
然后在index.php上...
Then on index.php...
if (isset($_GET['Message'])) {
print $_GET['Message'];
}
换句话说,index.php
将始终检查是否在url中传递了消息.如果有,则显示它.然后,只需在重定向中传递消息
In other words, index.php
will always check if it's being passed a message in the url. If there is one, display it. Then, just pass the message in the redirect
如果您真的想使用模式弹出窗口,请生成js ...
if you really want to use a modal popup, generate the js...
if (isset($_GET['Message'])) {
print '<script type="text/javascript">alert("' . $_GET['Message'] . '");</script>';
}
请注意,如果您在消息中使用引号,除非您将其转义,否则这将中断
Note that this will break if you use quotes in the message unless you escape them
这篇关于PHP:提供警报弹出窗口,然后重定向页面的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!