本文介绍了JavaFX:TableView:用于默认排序的列的箭头的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个具有表视图的简单Java fx应用程序.表格视图显示了按特定顺序排序的一些数据.有没有一种方法可以显示箭头(默认情况下),该箭头指示数据已经按照该顺序排序了?
I have a simple java fx application which has a table view. The table view shows some data that is sorted in a certain order. Is there a way to show the arrow(by default) indicating that the data has been sorted in that order?
我的代码如下:
import java.util.Collections;
import javafx.application.Application;
import javafx.beans.property.SimpleIntegerProperty;
import javafx.beans.property.SimpleStringProperty;
import javafx.collections.FXCollections;
import javafx.collections.ObservableList;
import javafx.scene.Group;
import javafx.scene.Scene;
import javafx.scene.control.Label;
import javafx.scene.control.TableColumn;
import javafx.scene.control.TableView;
import javafx.scene.control.cell.PropertyValueFactory;
import javafx.scene.layout.VBox;
import javafx.scene.text.Font;
import javafx.stage.Stage;
public class TableViewSample extends Application
{
private TableView<Person> tableView = new TableView<Person>();
private final ObservableList<Person> data = FXCollections.observableArrayList(new Person(
"Allan", "Smith", "[email protected]",
22), new Person("Zombie", "Jack",
"[email protected]", 23), new Person(
"Michael", "Rock", "[email protected]",
24), new Person("Best", "Jones",
"[email protected]", 11), new Person(
"Michael", "Brown",
"[email protected]", 14));
public static void main(String[] args)
{
launch(args);
}
@Override
public void start(Stage stage)
{
Scene scene = new Scene(new Group());
stage.setTitle("Table View Sample");
stage.setWidth(650);
stage.setHeight(500);
final Label label = new Label("Roster");
label.setFont(new Font("Arial", 10));
tableView.setEditable(true);
TableColumn firstNameCol = new TableColumn("First Name");
firstNameCol.setMinWidth(100);
firstNameCol.setCellValueFactory(new PropertyValueFactory<Person, String>("firstName"));
TableColumn lastNameCol = new TableColumn("Last Name");
lastNameCol.setMinWidth(100);
lastNameCol.setCellValueFactory(new PropertyValueFactory<Person, String>("lastName"));
TableColumn emailCol = new TableColumn("Email");
emailCol.setMinWidth(200);
emailCol.setCellValueFactory(new PropertyValueFactory<Person, String>("email"));
TableColumn ageCol = new TableColumn("Age");
ageCol.setMinWidth(200);
ageCol.setCellValueFactory(new PropertyValueFactory<Person, Integer>("age"));
Collections.sort(data);
tableView.setItems(data);
tableView.getColumns().addAll(firstNameCol, lastNameCol, emailCol, ageCol);
final VBox vbox = new VBox();
vbox.setSpacing(5);
vbox.getChildren().addAll(label, tableView);
((Group) scene.getRoot()).getChildren().addAll(vbox);
stage.setScene(scene);
stage.show();
}
public static class Person implements Comparable<Person>
{
private final SimpleStringProperty firstName;
private final SimpleStringProperty lastName;
private final SimpleStringProperty email;
private final SimpleIntegerProperty age;
private Person(String fName, String lName, String email, int age)
{
this.firstName = new SimpleStringProperty(fName);
this.lastName = new SimpleStringProperty(lName);
this.email = new SimpleStringProperty(email);
this.age = new SimpleIntegerProperty(age);
}
public SimpleIntegerProperty getAge()
{
return age;
}
public void setAge(int passedAge)
{
age.set(passedAge);
}
public String getFirstName()
{
return firstName.get();
}
public void setFirstName(String fName)
{
firstName.set(fName);
}
public String getLastName()
{
return lastName.get();
}
public void setLastName(String fName)
{
lastName.set(fName);
}
public String getEmail()
{
return email.get();
}
public void setEmail(String fName)
{
email.set(fName);
}
public int compareTo(Person o)
{
return firstName.get().compareTo(o.getFirstName());
}
}
}
推荐答案
尝试
...
firstNameCol.setSortType(TableColumn.SortType.ASCENDING);
...
tableView.setItems(data);
tableView.getColumns().addAll(firstNameCol, lastNameCol, emailCol, ageCol);
tableView.getSortOrder().add(firstNameCol);
...
另请参见以下讨论: Javafx:对列进行重新排序在TableView中.
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