从 2 个数组中获取唯一值

问题描述

我有 2 个数组，我试图仅从它们获取唯一值.所以我不只是想删除重复项，我实际上是在尝试删除两个重复项.

I have 2 arrays that I'm trying to get the unique values only from them. So I'm not just trying to remove duplicates, I'm actually trying to remove both duplicates.

所以如果我得到这样的 2 个数组:

So if I'm getting the 2 arrays like this:

$array1 = array();
$array2 = array();

foreach($values1 as $value1){ //output: $array1 = 10, 15, 20, 25;
    $array1[] = $value1;
}

foreach($values2 as $value2){ //output: $array2 = 10, 15, 100, 150;
    $array2[] = $value2;
}

我正在寻找的最终输出是

The final output I'm looking for is

$output = 20, 25, 100, 150;

有什么巧妙的方法来完成这项工作吗?

Any neat way to getting this done?

推荐答案

其他答案都在正确的轨道上，但是 array_diff 仅适用于一个方向——即.它返回存在于第一个数组中但不存在于任何其他数组中的值.

The other answers are on the right track, but array_diff only works in one direction -- ie. it returns the values that exist in the first array given that aren't in any others.

您要做的是获取两个方向的差异，然后将差异合并在一起:

What you want to do is get the difference in both directions and then merge the differences together:

$array1 = array(10, 15, 20, 25);
$array2 = array(10, 15, 100, 150);
$output = array_merge(array_diff($array1, $array2), array_diff($array2, $array1));
// $output will be (20, 25, 100, 150);

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