SAS LOOP - 从具有值的记录创建列

问题描述

假设我有随机的诊断代码，例如 001、v58、...、142、.. 如何根据记录为 1 的代码构造列?

Suppose i have random diagnostic codes, such as 001, v58, ..., 142,.. How can I construct columns from the codes which is 1 for the records?

Input:
            id found  code

            1   1      001
            2   0      v58
            3   1      v58
            4   1      003
            5   0      v58
    ......
    ......
    15000   0      v58

Output:
id code_001 code_v58 code_003 .......
1    1       0        0
2    0       0        0
3    0       1        0
4    1       0        0
5    0       0        0
.........
.........

推荐答案

您将需要 TRANSPOSE 值并根据数据(code 的值)命名透视列) 带有 ID 语句.

You will want to TRANSPOSE the values and name the pivoted columns according to data (value of code) with an ID statement.

示例:

在现实世界的数据中，缺失的诊断通常会被标记为零，这必须在后续步骤中完成.

In real world data it is often the case that missing diagnoses will be flagged zero, and that has to be done in a subsequent step.

data have;
input id found  code $;
datalines;
1   1      001
2   0      v58
2   1      003  /* second diagnosis result for patient 2 */
3   1      v58
4   1      003
5   0      v58
;

proc transpose data=have out=want(drop=_name_) prefix=code_;
  by id;
  id code;   * column name becomes <prefix><code>;
  var found;
run;

* missing occurs when an id was not diagnosed with a code;
* if that means the flag should be zero (for logistic modeling perhaps)
* the missings need to be changed to zeroes;

data want;
  set want;
  array codes code_:;
  do _n_ = 1 to dim(codes);   /* repurpose automatic variable _n_ for loop index */
    if missing(codes(_n_)) then codes(_n_) = 0;
  end;
run;

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