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问题描述

编写SQL查询

1.能够识别患者保险公司名称的数据

2.能够描述患者地理位置的数据

3.显示手术期间药物总费用的汇总栏





HOSPITALEMRDATA

dbo 。保险提供商

ProviderName

城市

状态

邮编



dbo.Patiens

PatientID

PatientName

出生日期

MRN



dbo.PatientVisits

PatientVisitID

PatientID

AdmissionDate

DischargeDate

InsuranceProviderID

PatientCity

PatientState

PatientZip





SURGERYDATA.DBO

dbo.Drug_Administration

DrugAdministraionID

CaseID

DrugID

TimeGiven

QuantityGiven



dbo.Cases

CaseID

MRN

SurgeryData

SurgeryStart

SurgeryFinish

ServiceLineID



dbo.Drugs

DrugID

名称

成本



dbo.ServiceLine

ServiceLineID

ServiceLineName



我是什么尝试过:



从HospitalEmrData.dbo.PatientVisit,InsuranceProviders,选择PatientName,PatientCity,PatientState,PatientZip,ProviderName

,患者





从这里被困......

Write an SQL Query
1. Data capable of identifying the patient’s insurance company name
2. Data capable of describing the patient’s geographic location
3. An aggregation column showing the total cost of drugs administered during surgery


HOSPITALEMRDATA
dbo.InsuranceProvider
ProviderName
City
State
Zip

dbo.Patiens
PatientID
PatientName
Birthdate
MRN

dbo.PatientVisits
PatientVisitID
PatientID
AdmissionDate
DischargeDate
InsuranceProviderID
PatientCity
PatientState
PatientZip


SURGERYDATA.DBO
dbo.Drug_Administration
DrugAdministraionID
CaseID
DrugID
TimeGiven
QuantityGiven

dbo.Cases
CaseID
MRN
SurgeryData
SurgeryStart
SurgeryFinish
ServiceLineID

dbo.Drugs
DrugID
Name
Cost

dbo.ServiceLine
ServiceLineID
ServiceLineName

What I have tried:

Select PatientName, PatientCity, PatientState, PatientZip, ProviderName
from HospitalEmrData.dbo.PatientVisit, InsuranceProviders, Patients


Stuck from here...

推荐答案

Quote:
Select PatientName, PatientCity, PatientState, PatientZip, ProviderName
from HospitalEmrData.dbo.PatientVisit, InsuranceProviders, Patients





对不起,但似乎你是非常初学者。我建议从这里开始: [],因为你是使用 [],返回 []。

根据具体情况,您需要使用 INNER,LEFT或RIGHT JOIN ,但不能 CROSS JOIN



BTW:这是你的功课。你必须自己解决。



Sorry, but it seems you're very beginner. I'd suggest to start here: Visual Representation of SQL Joins[^], because you're using CROSS JOIN[^], which returns the Cartesian product[^] of the tables involved in the join.
Depending on situation, you need to use INNER, LEFT or RIGHT JOIN, but not CROSS JOIN!

BTW: It's your homework. You have to resolve it yourself.


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08-26 06:02