问题描述
我正在尝试编写一个 numpy 函数，该函数会对其自身进行迭代以更新其函数的值.例如，如果 Random_numb 等于 [50，74，5，69，50] .因此，对于第一个计算，计算将类似于 10 * 50 = 500 ，方程式为 Starting_val = Starting_val * Random_numb .Starting_Val等于 500 ，因此对于第二次计算，它将为 500 * 74 = 37000 .将 Startin_Val 从 500 更新为 37000 .在进行计算时，依次遍历 Random_numb ，使用元素1: 50 进行计算1，使用元素2 74 进行计算2，依此类推.计算将一直进行到 Random_numb 数组的末尾.
I am trying to write a numpy function that iterates with itself to update the values of its function. If for example Random_numb was equal to [50, 74, 5, 69, 50]. So the calculations would go like, 10* 50 = 500 for the first calculation, with the equation Starting_val = Starting_val * Random_numb. The Starting_Val would equal to 500 so for the second calculation it would go as 500 * 74 = 37000. Updating the Startin_Val to 37000 from 500. Iterating through the Random_numb as it does the calculations, using element 1: 50 for calculation 1 and element 2 74 for calculation 2 and so on. The calculations would go on until the end of the Random_numb array.
import numpy as np
Starting_val = 10
Random_numb = random.randint(100, size=(5))
Starting_val = Starting_val * Random_numb
推荐答案
IIUC，您正在寻找 产品 :
IIUC you're looking for prod:
import numpy as np
Starting_val = 10
Random_numb = np.array([50, 74, 5, 69, 50])
Random_numb.prod(initial=Starting_val)
#638250000
如果您对数组的乘法值感兴趣，它将为 cumprod :
If you're interested in the multiplied values of the array it'll be cumprod:
Starting_val * Random_numb.cumprod()
# array([ 500, 37000, 185000, 12765000, 638250000])
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