scala 元组解包

问题描述

我知道这个问题已经多次以不同的方式出现.但我仍然不清楚.有没有办法实现以下目标.

I know this question has come up many times in different ways. But it is still not clear to me. Is there a way to achieve the following.

def foo(a:Int, b:Int) = {}

foo(a,b) //right way to invoke foo

foo(getParams) // is there a way to get this working without explicitly unpacking the tuple??

def getParams = {
   //Some calculations
   (a,b)  //where a & b are Int
}

推荐答案

这是一个两步过程.先把 foo 变成一个函数，然后在它上面调用 tupled 使它成为一个元组的函数.

It's a two step procedure. First turn foo into a function, then call tupled on it to make it a function of a tuple.

(foo _).tupled(getParams)

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