问题描述
假设我们有一个类A，它包含作为同一类的成员：
Say we have a class A that contains as a member of the same class:
Class A{
const A &a;
}
我想创建一个参数化的构造函数，我不想定义类的复制构造函数。
I want to create a parametized constructor that passed the value of that member, but I do not want to define the copy constructor of the class.
A(const A& memberA): a(memberA) {}
如何表示编译器这样的东西？
How could indicate the compiler such thing?
感谢
推荐答案
一个构造函数只需要引用它构造的类一个复制构造函数，无论你想要它是一个或没有。复制构造函数定义如下：
A constructor that can take just a reference to the class it constructs is a copy constructor, whether you want it to be one or not. Copy constructors are defined thus:
你可以声明它 explicit 来限制类的复制（防止 A a = A（）），但它仍然是一个复制构造函数，只要它有该签名。
You could declare it explicit to restrict how the class can be copied (preventing A a = A() for example), but it's still a copy constructor as long as it has that signature.
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