在每个列表元素上调用int()函数?

本文介绍了在每个列表元素上调用int()函数?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

我有一个包含数字字符串的列表，如下所示:

I have a list with numeric strings, like so:

numbers = ['1', '5', '10', '8'];

我想将每个列表元素都转换为整数，所以它看起来像这样:

I would like to convert every list element to integer, so it would look like this:

numbers = [1, 5, 10, 8];

我可以使用循环来做到这一点，就像这样:

I could do it using a loop, like so:

new_numbers = [];
for n in numbers:
    new_numbers.append(int(n));
numbers = new_numbers;

它必须很丑吗?我敢肯定，在一行代码中，还有一种更Python化的方法可以做到这一点.请帮帮我.

Does it have to be so ugly? I'm sure there is a more pythonic way to do this in a one line of code. Please help me out.