本文介绍了SQL Server 查询 - 计算房间的可用性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个表名 RoomInventory
有如下数据
I have a table name RoomInventory
that has data like below
Date (Date) RoomsAvailable (int)
1-Jul-2015 30
2-Jul-2015 30
3-Jul-2015 30
5-Jul-2015 28
6-Jul-2015 28
7-Jul-2015 28
8-Jul-2015 30
9-Jul-2015 30
10-Jul-2015 26
11-Jul-2015 28
12-Jul-2015 28
我想要的结果如下:
StartDate EndDate RoomsAvailable
----------------------------------------------
1-Jul-2015 3-Jul-2015 30
5-Jul-2015 7-Jul-2015 28
8-Jul-2015 9-Jul-2015 30
10-Jul-2015 10-Jul-2015 26
11-Jul-2015 12-Jul-2015 28
请帮忙..
推荐答案
试试下面的查询
DECLARE @Reservation TABLE ( BookDate DATE, ROOMS INT)
INSERT INTO @Reservation VALUES
('1-Jul-2015',30 ),
('2-Jul-2015',30 ),
('3-Jul-2015',30 ),
('5-Jul-2015',28 ),
('6-Jul-2015',28 ),
('7-Jul-2015',28 ),
('8-Jul-2015',30 ),
('9-Jul-2015',30 ),
('10-Jul-2015',26 ),
('11-Jul-2015',28 ),
('12-Jul-2015',28 )
;WITH
cte AS (
select ROW_NUMBER() OVER(ORDER BY BookDate) AS RowNumber,
[ROOMS], BookDate FROM @Reservation
),
cte2 as (
SELECT TOP 1 RowNumber, 1 as GroupNumber, [ROOMS], BookDate FROM cte ORDER BY RowNumber
UNION ALL
SELECT c1.RowNumber,
CASE WHEN c2.[ROOMS] <> c1.[ROOMS] then c2.GroupNumber + 1 ELSE c2.GroupNumber END AS GroupNumber, c1.[ROOMS], c1.BookDate
FROM cte2 c2 join cte c1 on c1.RowNumber = c2.RowNumber + 1
)
SELECT Start_Date, End_Date, Rooms
FROM
( SELECT MIN(BookDate) AS START_DATE, MAX(BookDate) AS END_DATE ,ROOMS, GroupNumber
FROM cte2
GROUP BY ROOMS ,GroupNumber
) a
这篇关于SQL Server 查询 - 计算房间的可用性的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!