Mule JAXB对象到XML Transformer抛出JAXBException

问题描述

我正在使用Mule 3.6。我有一个用JAXB绑定注释的对象，我试图将它转换为Mule中的XML。每当我尝试这样做时，我得到一个 javax.xml.bind.JAXBException：com.mj.metal.object不包含ObjectFactory.class或jaxb.in​​dex 。我的变换器定义为：

I am using Mule 3.6. I have an object which is annotated with JAXB bindings and I am trying to convert it into XML in Mule. Whenever I try to do so, I get a javax.xml.bind.JAXBException: "com.mj.metal.object" doesn't contain ObjectFactory.class or jaxb.index. My transformer are defined as:

<mulexml:jaxb-context name="JAXB_Context" packageNames="com.mj.metal.object"/>
<mulexml:jaxb-object-to-xml-transformer mimeType="application/xml" jaxbContext-ref="JAXB_Context" doc:name="JAXB Object to XML"/>

此包包含要进行转换的类。其中之一是：

This package contains my classes to which the transformation is to be made. One of them is:

@XmlRootElement(name = "REPORT")
@XmlAccessorType(XmlAccessType.FIELD)
public class Report {

    @XmlElement(name = "HEADER")
    private Header header;
    @XmlElementWrapper(name = "ITEMS")
    @XmlElement(name = "ITEM")
    private List<Item> items;

    public Report() {
        super();
        header = new Header();
        items = new ArrayList<Item>();
    }

    public Header getHeader() {
        return header;
    }

    public List<Item> getItems() {
        return items;
    }

    public void setHeader(Header header) {
        this.header = header;
    }

    public void setItems(List<Item> items) {
        this.items = items;
    }

    @Override
    public String toString() {
        return "\nReport [header=" + header + "\nitems=" + items + "]";
    }
}

如何解决此问题？

推荐答案

您需要在类路径中添加一个jaxb.in​​dex文件，以便JAXB能够知道它应该将XML数据结构映射到哪些类。

You need to add a jaxb.index file to your classpath so that JAXB is able to know which classes it should map your XML data structures to.

jaxb.in​​dex文件只不过是包含JAXB注释的包含类的列表。只需输入简单的名称（不是完全分类的名称就足够了）。

The jaxb.index file is nothing more than a list of the classes on the containing package that have JAXB annotations. Simply typing in their simple names (not their fully classified names is enough).

这些链接可能会对您有所帮助：

These links might help you:

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