比较字符(ARM汇编)

问题描述

我正在尝试将我的汇编代码中的字符数组中的字符与字符进行比较.

I'm trying to compare a Character from a Char-Array with a char in my assembly code.

这是我用来启动汇编代码的C代码:

This is the C-Code I use to start the assembly code:

char a[] = "abc";
char b = 'a';
int size = 3;

int d = _asm_main(a);
printf("Char a: %s\n",a);
printf("Erg:%d\n",d);

这是汇编代码:

_asm_main:

push {r6,r7,r8,lr}

mov r8,r0

ldr r7,[r8,#2]
mov r6,r7
b compare

compare:

cmp r6,#'c'
beq true
b false

true:

mov r0,#1
b end

false:

mov r0,#2
b end

end:

pop {r6,r7,r8,pc}

BX lr

它适用于'c'，但是如果我尝试使用'a'或'b'，我总是陷入错误的寓言中.我不明白为什么它对这三个之一有效，而对另外两个无效.

It works for 'c' but if I try it with 'a' or 'b' I always get into the false lable. I don't get why it works for one of the three and not for the other two.

推荐答案

使用ldrb处理ASCII字节和gdb调试器的粗略说明.

A crude illustration using ldrb to deal with the ASCII byte and gdb debugger.

.data
        array:          .string "abc"
.text
        .global _start
_start:
        nop
        ldr r0,=array
        ldrb r1, [r0,#0]
        ldrb r2, [r0,#1]
        ldrb r3, [r0,#2]
...

gdb:

16              ldr r0,=array
(gdb) si
17              ldrb r1, [r0,#0]
(gdb)
18              ldrb r2, [r0,#1]
(gdb)
19              ldrb r3, [r0,#2]
(gdb)
_exit () at stuff.s:25
25              mov r7, #1
(gdb) i r
r0             0x20094  131220
r1             0x61     97
r2             0x62     98
r3             0x63     99

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