JSF-有条件地显示两个对话框之一

问题描述

我的页面上有两个Primefaces p:dialogs，我有两个按钮来显示它们(一个是删除按钮，另一个是编辑按钮).

I have two Primefaces p:dialogs in my page and I have two buttons to display them (the one is a delete button, the other one is an edit button).

我将对话框的可见属性设置如下:visible="#{fn:length(bean.selectedItems) gt 0}用于删除按钮，而visible="#{fn:length(bean.selectedItems) eq 1}，因此我可以删除多个元素，但只能同时编辑一个.

I set the visible attribute of the dialogs as follows: visible="#{fn:length(bean.selectedItems) gt 0} for the delete button and visible="#{fn:length(bean.selectedItems) eq 1}, so I can delete multiple elements, but only edit one at the same time.

现在，该bean是ViewScoped，因此，如果恰好选择了一项，并且有一个没有按下ajax提交的commandButton，则将显示两个对话框，这显然不是我想要的.

Now the bean is ViewScoped, so if there is exactly one item selected, and there is a commandButton without ajax submit pressed, both of the dialogs are displayed, which obviously is not what I want.

仅在需要时才显示适当对话框的最简单方法是什么?

What is the easiest way to show the appropriate dialog only when needed?

我不想为此设置额外的bean属性，因此让我们考虑一个简单的解决方案.还有另一种方法吗?也许将动作名称设置为视图范围参数?还是使用呈现的属性并通过javascript回调管理显示/隐藏?

I don't want to set an extra bean attribute for that, so let's consider that a trivial solution. Is there another way? Maybe setting the name of the action to a view scoped parameter? Or using the rendered attributes and managing the show/hide from javascript callback?

推荐答案

我认为正确的方法是

<p:commandButton value="DELETE"
                 onclick="deleteDialog.show()"
                 disabled="#{fn:length(bean.selectedItems) eq 0}" />

<p:commandButton value="EDIT"
                 onclick="editDialog.show()"
                 disabled="#{fn:length(bean.selectedItems) ne 1}" />

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