更新联系人中的多个电话号码

问题描述

我尝试使用以下方法更新特定联系人的多个电话号码代码:

I am tried to update multiple phone numbers of specific contact using followingcode:

for(int j=0;j<allPhoneNumbersLength;j++)
{
PhoneInfo phoneInfo = (PhoneInfo) allPhoneNumbers.elementAt(j);
String phoneValue = phoneInfo.getValue();
int phoneType = phoneInfo.getIndex(); // phoneType = Phone.TYPE_HOME,  Phone.TYPE_WORK, etc
ContentProviderOperation.Builder builderPhone = ContentProviderOperation.newUpdate(Data.CONTENT_URI)
.withSelection(ContactsContract.Data.CONTACT_ID + "=?"+" AND "+ContactsContract.Data.MIMETYPE + "=?" + " AND "+Phone.TYPE+"=?",  new String[]{String.valueOf(contactID), Phone.CONTENT_ITEM_TYPE, String.valueOf(phoneType)});
if(phoneType == Phone.TYPE_HOME)
{
builderPhone.withValue(Phone.NUMBER, phoneValue)
.withValue(Phone.TYPE, Phone.TYPE_HOME);
}
else if(phoneType == Phone.TYPE_WORK)
{
builderPhone.withValue(Phone.NUMBER, phoneValue)
.withValue(Phone.TYPE, Phone.TYPE_WORK);
}
else if(phoneType == Phone.TYPE_FAX_HOME)
{
builderPhone.withValue(Phone.NUMBER, phoneValue)
.withValue(Phone.TYPE, Phone.TYPE_FAX_HOME);
}
op_list.add(builderPhone.build());

}
getContentResolver().applyBatch(ContactsContract.AUTHORITY, op_list);

使用此代码，我尝试更新三个数字，但仅更新"TYPE_FAX_HOME"号码已更新，另外两个号码已从联系人中删除.

Using this code I am trying to update three numbers, but only "TYPE_FAX_HOME"number is updated and other two numbers are removed from contact.

请帮助我.

推荐答案

我从您的代码中了解到，您将相同电话号码值用于这三种类型.因此，在显示时，android将仅显示其中的 1 个联系人.但是，如果您实际上编辑该联系人，则可以看到，所有3种类型均填充了相同的编号.

I've learnt from your code that, you're using the same phone number value for all the 3 types. Hence, while displaying, android will display only 1 of them for the contact. But if you actually edit the contact, there you can see that, all the 3 types have been populated with the same number.

P.S:我假设您要为其进行编辑的联系人已经为所有3种类型填充了一些号码.如果没有，请创建它们，然后尝试运行您的代码.

P.S: I'm assuming that the contact for which you're trying to do the edit, already has some number populated for all the 3 types. If not, please create them and then try running your code.

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