使用 BeautifulSoup 根据 name 属性获取属性值

问题描述

我想根据名称打印一个属性值，举个例子

我想做这样的事情

soup = BeautifulSoup(f) # f 是一些包含上述元标记的 HTML对于汤中的元标签(meta"):如果 meta_tag[name"] == City":打印(meta_tag [内容"])

上面的代码给出了一个KeyError: 'name'，我相信这是因为BeatifulSoup使用了name，所以它不能用作关键字参数.

解决方案

很简单，用下面的-

>>>从 bs4 导入 BeautifulSoup>>>汤 = BeautifulSoup('<META NAME="City" content="Austin">')>>>汤.find(元"，{名称":城市"})<meta name="City" content="Austin"/>>>>汤.find("meta", {"name":"City"})['content']你是奥斯汀

如果有什么不清楚的，请发表评论.

I want to print an attribute value based on its name, take for example

<META NAME="City" content="Austin">

I want to do something like this

soup = BeautifulSoup(f)  # f is some HTML containing the above meta tag
for meta_tag in soup("meta"):
    if meta_tag["name"] == "City":
        print(meta_tag["content"])

The above code give a KeyError: 'name', I believe this is because name is used by BeatifulSoup so it can't be used as a keyword argument.

解决方案

It's pretty simple, use the following -

>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<META NAME="City" content="Austin">')
>>> soup.find("meta", {"name":"City"})
<meta name="City" content="Austin" />
>>> soup.find("meta", {"name":"City"})['content']
u'Austin'

Leave a comment if anything is not clear.

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