停止从子组件触发父组件波纹

问题描述

假设我有一个简单的代码，例如:

Let's say I have a simple code like:

<ListItem
  button={true}
>
  <Typography variant='caption' color='primary'>
            {value}
  </Typography>
  <Button
    onClick={foo}
  >
    Button
  </Button>
</ListItem>

当我单击ListItem内的任何内容时，都会触发涟漪效应，这是可以的，但是当我单击按钮时，我不希望触发父组件的涟漪效应.我该怎么办?

When I click anything inside the ListItem the ripple effect is trigger, which is ok, but when I click the button I don't want the ripple effect of the parent component to be triggered. How do I do that?

推荐答案

您可以尝试使用ListItem的disableRipple属性.单击按钮时将其设置为true，单击列表项时将其设置为false，例如:

You can try to use disableRipple property of ListItem. Set it to true when clicking on button and set it to false when clicking on list item, something like:

const foo = () => this.setState(prevState => ({
  ...prevState,
  parentDisableRipple: true
}));
const enableRipple = () => this.state.parentDisableRipple && this.setState(prevState => ({
  ...prevState,
  parentDisableRipple: false
}));

return (
  <div>
    <Hello name={this.state.name} />
    <p>
      Start editing to see some magic happen :)
    </p>

    <ListItem button={true}
              disableRipple={this.state.parentDisableRipple}
              onClick={enableRipple()}>
      <Typography variant='caption' color='primary'>
        {value}
      </Typography>
      <Button onClick={foo} >Button</Button>
    </ListItem>
  </div>
);

我创建了一个 STACKBLITZ 来玩

更新

有一个(@vasanthcullen已在此处提及).

There is a better solution by @Domino987 using onMouseDown and event.stopPropagation() (already mentioned here by @vasanthcullen).

我使用此解决方案更新了STACKBLITZ

I updated my STACKBLITZ with this solution

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