本文介绍了在 Swift 中休眠或延迟 Timer 线程的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在尝试在自重复计时器上创建一两秒的延迟.这就是我创建计时器的方式:

I have been trying to create a delay of one or two seconds on a self repeating timer. This is how I create the timer:

currentThread = Timer.scheduledTimer(timeInterval: 0.001, target: self, selector: #selector(Movement.updatePosition), userInfo: nil, repeats: true)

所以计时器不断地运行方法updatePosition().但是,我在该方法中有一个 if 语句,我希望将计时器延迟几秒钟:

So the timer constantly runs the method updatePosition(). However, I have an if statement within that method where I would like to have the timer be delayed for a few seconds:

if distance <= respawnDistance * 0.1 {
    // Delay timer for 1 second
}

我当时认为我可以做到这一点:

And I was thinking that I could do this:

currentThread.invalidate()

然后只需创建另一个在 1 秒后运行的计时器,这会导致重新激活前一个计时器.但是,我认为如果有办法让当前的 Timer 休眠,那效率会很低吗?

And then just create another Timer that runs after 1 second, which leads to the reactivation of the previous timer. However, I think that would be inefficient if there is a way to sleep the current Timer?

推荐答案

NSTimer 不是那么准确.它的最大分辨率约为 50 - 100 毫秒.无论如何,您可以添加一个变量来控制计时器的触发:

NSTimer is not that accurate. Its maximum resolution is somewhere around 50 - 100ms. Anyhow, you can add a variable to control the firing of the timer:

var doNotUpdate = false

if distance <= respawnDistance * 0.1 {
    doNotUpdate = true
    DispatchQueue.main.asyncAfter(deadline: .now() + 1.0) {
        doNotUpdate = false
    }
}

func updatePosition() {
    if doNotUpdate { return }

    // update your position
}

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08-16 07:59