我怎么访问的jQuery AJAX函数返回的字符串数组

问题描述

我有以下的code，搜索键入搜索框的onkeyup事件的人物。

I have the following code that searches the characters typed in the search box with the onkeyup event.

$("#keywords").keyup(function () {
    var kw = $("#keywords").val();
    if (kw != '') {
        var url = "<?php echo base_url().'index.php/simpromotions/livesearch/';?>" + kw;
        $.ajax({
            type: "POST",
            url: url,
            datatype: "json",
            success: function (data) {
                **alert(data);**
                $.each(data,function(ptitle, category){
                    $("#results").html('<label>'+ptitle+': '+category+'</label><br>');
                }
            }
        });
    }else{
        $("#results").html("");
        return false;
    }
});

在时，我提醒数据上面的code 这里显示以下数组字符串。

In the above code when I alert the data it displayes the following array string.

{"pcode":"22","category":"NightTalk","ptitle":"HourlyNightTalk"}

我似乎无法访问点code ，类和 ptitle 因为我已经做了下一行。 （后警报）请帮我，我怎么能访问这三个！

I cant seem to access the pcode, category and ptitle as I have done in the next line. (after alert)Please help me how I can access the three!

推荐答案

这意味着数据是一个字符串，并且响应是一个简单的JSON恩codeD对象，不是阵列

That means data is a string, and the response is a simple JSON encoded object, not an array.

您必须首先解析响应。你可以让jQuery的通过固定的dataType 属性为你做这个：

You have to parse the response first. You can let jQuery do this for you by fixing the dataType property:

dataType: "json" // dataType, not datatype

在回调，数据将是一个JavaScript对象，现在，你只需要直接访问其属性（了解更多关于的）：

Inside the callback, data will be a JavaScript object now and you just directly access its properties (learn more about objects in MDN - Working with Objects):

success: function (data) {
    $("#results").html('<label>'+data.ptitle+': '+data.category+'</label><br>');
}

这是没有意义的使用 $。每个在这里。 看一看文档了解它做什么以及它是如何工作的。

It doesn't make sense to use $.each here. Have a look at the documentation to learn what it does and how it works.

您提到，有时候，你实际上得到一个数组回来。在这种情况下，你可能想使用 $。每个。为了让您的code简单，我建议为总是从服务器返回一个数组：

You mentioned that sometimes you actually get an array back. In that case you probably want to use $.each. To make your code simpler, I recommend to always return an array from the server:

var $results = $('#results');
$results.empty();
$.each(data, function(i, obj){
    $results.append('<label>'+obj.ptitle+' is in '+obj.category+'</label><br>');
});

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