我如何创建一个从具有不同类型相同的通用类继承对象的列表？

问题描述

我和关闭试图找到一个答案，这个花了几个小时，我可能有问题正确地措辞的麻烦，这不利于。从本质上讲，我有一个抽象类：

I've spent a few hours on and off trying to find an answer to this, I'm probably having trouble with wording the question correctly, which doesn't help. Essentially, I have an abstract class:

public abstract class GenericType<T>
{ ... }

和一堆，从它继承的类：

And a bunch of classes that inherit from it:

public class AType: GenericType<A>
{ ... }

public class BType: GenericType<B>
{ ... }

...

最后，我有希望遏制，从GenericType继承的事情的清单另一个类，无论T，即Atypes，BTypes等的价值。

Lastly, I have another class that wants to contain a list of things that inherit from GenericType, regardless of the value of T, i.e. Atypes, BTypes and so on.

我的第一个尝试均使用列表< GenericType> 和列表< GenericType<对象>> 但niether的给我任何的喜悦。

My first attempts were to use List<GenericType> and List<GenericType<Object>> but niether's given me any joy.

这是我应该怎么会对此有什么建议？ ！不胜感谢

Any tips on how I should be going about this? Much thanks!

推荐答案

所以，如果我理解正确的话，你想是这样的：

So, if I understand correctly, you want something like this:

List<GenericType>

可以包含 ATYPE 的任何实例， B型等，您只需通过这样做 GenericType< T> 本身的一个子类GenericType ：

Which can contain any instance of AType, BType, etc. You simply do this by making GenericType<T> itself a subclass of GenericType:

public class GenericType { }
public class GenericType<T> : GenericType { }
public class AType : GenericType<int> { }
public class BType : GenericType<int> { }

您可以再坚持任何实例成列表< GenericType> 。

You can then stick any instance into a List<GenericType>.

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