表单提交后执行脚本

问题描述

我发现，在这个网站上提交 POST 表单而不离开页面的方法。在该脚本中，他们提供了如何在提交表单后进行功能的说明。这是脚本的样子：

I found, on this site a way to submit a POST form without leaving the page. In that script, they put instructions on how to have a function take place after the form's been submitted. Here's what the script looked like:

$(document).ready(function(){
$form = $('form');
$form.submit(function(){
  $.post($(this).attr('action'), $(this).serialize(), function(response){
  },'json');
  return false;
});
});​

他们说，在函数（响应）{和}，'json'）之间; 您可以在表单提交后指定其他JavaScript进行提醒等。我试过

They said, between function(response){ and },'json'); you can specify other JavaScript to take place like alerts etc. after the form's been submitted. I tried

$(document).ready(function(){
$form = $('form');
$form.submit(function(){
  $.post($(this).attr('action'), $(this).serialize(), function(response){
$('form').hide();
  },'json');
  return false;
});
});

不幸的是，这不起作用，有谁可以告诉我为什么？我设置了。请帮忙。感谢。

Unfortunately, that does not work, can anybody tell me why? I've set up a jsFiddle. Please help. Thanks.

推荐答案

使用$ .post，function（response）仅在成功结果后被调用，在服务器正在处理请求时在这个函数中做了错误的工作。

Using $.post, the "function(response)" is only called AFTER a successful result, so you have been misinformed about doing work within this function while the server is processing the request.

要在将请求发送到服务器后继续处理，请在$ .post调用后放置$（'form'）。hide（）：

To continue processing after sending the request to the server, place the $('form').hide() after the $.post call:

$form.submit(function(){
  $.post(
    $(this).attr('action'), $(this).serialize(),
    function(response){
    }
    ,'json'
  );
  $('form').hide();
  return false;
});

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