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问题描述

我写了一小段这样的代码:

I wrote a small piece of code like this:

template <class T>
void
test()
{
    T* ptr = nullptr;

    ptr = (T*)malloc(1 * sizeof(T));

    new ((void*)ptr) T(T());

    ptr = (T*)realloc(ptr, 2 * sizeof(T));

    new ((void*)(ptr + 1)) T(T());

    (ptr)->~T();
    (ptr + 1)->~T();

    free(ptr);
}

struct foo
{
    foo() : ptr(malloc(10)) {}
    ~foo() { free(ptr); }
    void* ptr;
};

int
main()
{
    test<int>(); // this is ok
    test<foo>(); // this is ok
    test<std::string>(); // memory error :(

    return 0;
};

当T为[int]或[foo]时,一切正常.但是将[std :: string]用作T会使valgrind报告这样的内存错误:

When T is [int] or [foo], everything works fine. But using [std::string] as T causes valgrind to report memory errors like this:

==18184== Memcheck, a memory error detector
==18184== Copyright (C) 2002-2015, and GNU GPL'd, by Julian Seward et al.
==18184== Using Valgrind-3.12.0 and LibVEX; rerun with -h for copyright info
==18184== Command: ./a.out
==18184==
==18184== Invalid free() / delete / delete[] / realloc()
==18184==    at 0x4C2C20A: operator delete(void*) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==18184==    by 0x401074: void test<std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >() (tmp.cpp:26)
==18184==    by 0x400CFC: main (tmp.cpp:44)
==18184==  Address 0x5a89e70 is 16 bytes inside a block of size 32 free'd
==18184==    at 0x4C2CC37: realloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==18184==    by 0x401042: void test<std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >() (tmp.cpp:22)
==18184==    by 0x400CFC: main (tmp.cpp:44)
==18184==  Block was alloc'd at
==18184==    at 0x4C2AB8D: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==18184==    by 0x40100F: void test<std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >() (tmp.cpp:18)
==18184==    by 0x400CFC: main (tmp.cpp:44)
==18184==
==18184==
==18184== HEAP SUMMARY:
==18184==     in use at exit: 0 bytes in 0 blocks
==18184==   total heap usage: 9 allocs, 10 frees, 72,856 bytes allocated
==18184==
==18184== All heap blocks were freed -- no leaks are possible
==18184==
==18184== For counts of detected and suppressed errors, rerun with: -v
==18184== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 0 from 0)

为什么只有[std :: string]会导致内存问题,而[foo]在ctor&中都具有malloc/freedtor吗?

why only [std::string] leads to memory problem while [foo] also has malloc/free in both ctor & dtor ?

我正在使用g ++ 6.2.1和valgrind 3.12.0

I'm using g++ 6.2.1 and valgrind 3.12.0

推荐答案

malloc() free() realloc()是C库函数,对C ++类,它们的构造函数和析构函数完全一无所知.

malloc(), free(), and realloc() are C library functions, that know absolutely nothing about C++ classes, their constructors, and destructors.

您正在将 malloc()与位置 new 一起使用,以使用 malloc -构造 std :: string -ed记忆.很好.

You are using malloc() with placement new to construct a std::string using malloc-ed memory. This is fine.

但是,您正在使用 realloc()重新分配已分配的内存.

But then, you're using realloc() to reallocate the allocated memory.

必须使用相应对象的复制/移动构造函数来完成在内存中复制/移动C ++对象的操作.不能使用 realloc()复制/移动内存中的C ++对象.

Copying/moving C++ objects in memory must be done using the respective objects' copy/move constructors. Copying/moving C++ objects in memory cannot be done with realloc().

执行此操作的唯一方法是 malloc()一个新的内存块,使用放置 new 调用对象的copy/move构造函数以进行复制/将它们移到新的内存块中,最后调用旧内存块中对象的析构函数,然后可以对其进行 free() -ed.

The only way to do this is to malloc() a new memory block, use placement new to invoke the objects' copy/move constructors in order to copy/move them into the new memory block, and finally invoke the destructor of the objects in the old memory block, after which it can be free()-ed.

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09-03 05:27