问题描述
我有一个problem上显示在设计一个组成部分。
I have a problem on displaying a component in Designer.
我认定的坏code，设计师不喜欢。
I identified the "bad" code that the designer does not like.
现在的问题是，仅在使用preprocessor指令，我不能注释它的设计时间。
Now, the problem is that I can't "comment" it for design time only using preprocessor directives.
现在，我试图（为VB.NET）以下
Now, I tried (for VB.NET) the following
#If Not Debug Then
Private Sub myWpfComponent_ItsEvent(sender, args) Handles myWpfComponent.ItsEvent
...
#End If
这......工作，而现在它是不显示在设计问题。
this... worked, and now it is displayed without problems in the designer.
现在的问题，我恐怕不能够调试正确组件。
The problem now that I am afraid do not be able to debug properly this component.
所以，我正在寻找一个解决办法点菜
So, I am searching for a workaround à la
#If Not DESIGN_TIME Then
#End If
有没有相似的地方？
Is there something similar?
推荐答案
您无法通过preprocessor实现这一目标。这是因为你可以运行调试的可执行文件之外VS（尝试一下，双击通过VS在调试模式中生成的EXE）。
You cannot achieve this through the preprocessor. This is because you can run a debug executable outside of VS (try it, double click on the EXE generated by VS under debug mode).
不管怎样，有一个运行时（不是基于preprocessor）属性，可能会有所帮助：
Anyway, there is a runtime (not preprocessor based) property that might help:
if (System.ComponentModel.LicenseManager.UsageMode ==
System.ComponentModel.LicenseUsageMode.Designtime)
这些网页将帮助并在运行时检查设计模式的其他方法：
These web pages will help and have other methods of checking for design mode at runtime:
http://msdn.microsoft.com/en-us/library/c58hb4bw(vs.71).aspx
http://weblogs.asp.net/fmarguerie/archive/2005/03/23/395658.aspx
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