本文介绍了"不能分配给物业:"任何"是不可改变的"错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

tiledViewsStack 包含的UIImageViews。我试图给数组的新中心坐标中的每个的UIImageView。不知道为什么我得到这个错误在for循环......

  VAR tiledViewsStack = [AnyObject]()    VAR randLocInt = INT()
    VAR randLoc = CGPoint()    在tiledViewsStack任何变种
    {
        randLocInt = INT((arc4random()* 10)%9)// 0,--- 8
        randLoc = allCenters [randLocInt] .CGPointValue()
        any.center = randLoc
    }


解决方案

需要做出 tiledViewsStack UIImages,不AnyObjects一叠。改变 VAR tiledViewsStack = [AnyObject]() VAR tiledViewsStack = [UIImageView的()

tiledViewsStack contains UIImageViews. I'm trying to give each UIImageView in the array a new center coordinate. Not sure why I'm getting this error for the last line in the for loop...

    var tiledViewsStack = [AnyObject]()

    var randLocInt = Int()
    var randLoc = CGPoint()

    for var any in tiledViewsStack
    {
        randLocInt = Int((arc4random()*10) % 9) // 0, --- 8
        randLoc = allCenters[randLocInt].CGPointValue()
        any.center = randLoc
    }
解决方案

Needed to make tiledViewsStack a stack of UIImages, not AnyObjects. Changed var tiledViewsStack = [AnyObject]() to var tiledViewsStack = [UIImageView]().

这篇关于"不能分配给物业:"任何"是不可改变的"错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-16 01:08